Counting Problems For Group 2(Due By EOC Feb. 25) - Lone Star College .

Transcription

Counting Problems for Group 2(Due by EOC Feb. 25)Arsenio Says, Show Me The Digits!1. a) From the digits 0, 1, 2, 3, 4, 5, 6, how many four-digit numbers with distinct digits can beconstructed? {0463 is not a four-digit number!}b) Of these, how many are even?Put A Sock In It Brad And Angelina.2. Mr. Smith left on a trip very early one morning. Not wishing to wake Mrs. Smith, Mr. Smithpacked in the dark. He had socks that were alike except for color, and his socks came in sixdifferent colors. Find the least number of socks he would have had to pack to be guaranteedof gettinga) at least one matching pair of socks.b) at least two matching pairs of socks.c) at least three matching pairs of socks.d) at least four matching pairs of socks.{Hint: He could actually pack as many as 6 socks and still not have a matching pair.1Color 11Color 21Color 31Color 41Color 51Color 6}Fair-minded Santa.3. a) In how many ways can 9 different toys be divided evenly among three children?{Hint: The distribution of toys boils down toWhich 3 toys for child #1Which 3 toys for child #2Which 3 toys for child #3}b) In how many ways can 9 identical toys be divided evenly among three children?

You’ve Seen One Painting, You’ve Seen Them All.4. An art collection on auction consisted of 4 Dalis, 5 Van Goghs, and 6 Picassos, and at the artauction were 5 art collectors. The society page reporter only observed the number of Dalis,Van Goghs, and Picassos acquired by each collector.a) How many different results could she have recorded for the sale of the Dalis if all weresold?b) How many different results could she have recorded for the sale of the Van Goghs if allwere sold?c) How many different results could she have recorded for the sale of the Picassos if all weresold?d) How many different results could she have recorded for the sale of all 15 paintings if allwere sold?{Hint: If we assume that each collector buys at least one Picasso then we’ll decide howmany each collector gets by choosing 4 spaces from the 5 spaces between the 6 Picassos:Collector# 1 gets 1PicassoCollector# 2 gets 2PicassosCollector Collector Collector# 3 gets 1 # 4 gets 1 # 5 gets 1PicassoPicasso PicassoSo if each must buy at least one, there are 5 C4 5 different ways that the 6 Picassoscould have been sold to the 5 collectors. To allow for the possibility that one or morecollectors didn’t buy any Picassos, we’ll pretend that there are actually 11 Picassos forthe 5 collectors to buy.Collector# 1 gets 3PicassosCollector# 2 gets 2PicassosCollector# 3 gets 1PicassoCollector# 4 gets 3PicassosCollector# 5 gets 2PicassosFrom the 10 spaces available, we’ll select 4. If we subtract 1 from each number ofPicassos assigned to each collector, we’ll have a way that the collectors could buy all 6Picassos even if some don’t buy any.Collector# 1 gets 2PicassosCollector# 2 gets 1PicassoCollector# 3 gets 0PicassosCollector# 4 gets 2PicassosCollector# 5 gets 1Picasso}

Fancy Dealing.5. How many different ways can you select 13 cards out of a standard 52 card deck so that the13 cards selected include at least 3 cards from each suit?{Hint: If you have at least 3 cards of each of the four suits, that gives you 12 cards. Youjust need one more card.}If you count it using13C3# of ways tochoose 3hearts13C3# of ways tochoose 3diamonds13C3# of ways tochoose 3spades13C3# of ways tochoose 3clubs40# of ways tochoose the13th cardYou will over count. Here’s why:Suppose that one time you choose 1, 2, and 3 of hearts, 1, 2, and 3 of diamonds, 1,2, and 3 of spades, 1, 2, and 3of clubs and your 13th card is the 4 of hearts, and the next time you choose 1, 2, and 4 of hearts, 1, 2, and 3 ofdiamonds, 1,2, and 3 of spades, 1, 2, and 3 of clubs and your 13th card is the 3 of hearts. Then the twoselections are the same, but they are counted as two different selections.Instead, try the approachWhich suitwill have 4cards?# of ways tochoose 4 ofthis kind# of ways tochoose 3 ofthe next kind# of ways tochoose 3 ofthe next kind# of ways tochoose 3 ofthe last kindDon’t Spend It All In One Place.6. We have 20,000 dollars that must be invested among 4 possible opportunities. Eachinvestment must be a whole number multiple of 1,000, and there are minimal investmentsthat must be made. The minimal investments are 2, 2, 3, and 4 thousand dollars,respectively. How many different investment strategies are available?{Hint: See the hint for #4.}Consider the sets A and B inside a universal set U. n (U ) n ( AB ) n ( A B ) , so we get B ) n ( A B ) . This rearranges into n ( A B ) n ( A) n ( B ) n (U ) n ( A B ) , and since n ( A B ) 0 , it must be that n ( A B ) n ( A) n ( B ) n (U ) . This means that the number of elements in the intersection ofthat n (U ) n ( A) n ( B ) n ( A

A and B is at least n ( A) n ( B ) n (U ) , and it also means that if n ( A) n ( B ) n (U ) 0 , thenit’s possible that n ( A B ) 0 . This result can be extended to the case of three sets as follows:n ( A B C ) n A ( B C ) n ( A) n ( B C ) n (U ) n ( A) n ( B ) n (C ) n (U ) n (U )so n ( A B C ) n ( A) n ( B ) n (C ) 2 n (U ) . It can further be extended to the case of foursets as follows:n ( A B C D ) n A ( B C D ) n ( A) n ( B C D ) n (U ),so n ( A) n ( B ) n ( C ) n ( D ) 2 n (U ) n (U )n ( A B C D ) n ( A) n ( B ) n (C ) n ( D ) 3 n (U ) .In general, you can show thatn ( A1 A2Ak ) n ( A1 ) n ( A2 ) n ( Ak ) ( k 1) n (U ) .Also, n ( AB ) n ( A) and n ( A B ) n ( B ) , so n ( A B ) min n ( A) , n ( B ) . In general,you can show that n ( A1A2Ak ) min n ( A1 ) , n ( A2 ) ,, n ( Ak ) .Read All About It.7. A paper carrier delivers 21 copies of the Citizen and 27 copies of the Daily Star to asubdivision having 40 houses. No house receives two copies of the same paper.a) What is the least number of houses to which 2 papers could be delivered?{Hint: See the previous discussion.}b) What is the greatest number of houses to which 2 papers could be delivered?c) If the paper carrier delivers 42 copies of the Citizen and 48 copies of the Daily Star to asubdivision having 40 houses with houses allowed to receive up to two copies of thesame paper, what is the least number of houses to which both papers are delivered?

Hardback Or Paperback Writer?8. Books were sold at a school book fair. Each book sold was either fiction or nonfiction andwas either hardback or paperback. The chair-person of the book-selling committee can’tremember exactly how many hardback books of fiction were sold, but he does rememberthat30 books were sold in all20 hardcover books were sold15 books of fiction were solda) What is the smallest possible number of hardback books of fiction sold?{Hint: See the hint for problem 7.}b) What is the largest possible number of hardback books of fiction sold?It’s All In The Name.9. a) Explain why in a group of 677 people with names spelled from the letters A-Z, at least twopeople share first and last names beginning with the same letters. For example, thenames could be Chris Jones and Charles Jackson.{Hint: How many different ways are there for the beginning letters of a person’s firstand last names?# of choices for the first # of choices for the firstletter of the first nameletter of the last name}b) What is the fewest number of people needed to guarantee that at least two people sharefirst, middle, and last names beginning with the same letters?(Assume that everyone hasfirst , middle, and last names.) For example, the names could be Chris Allen Jones andCharles Arnold Jackson.c) What is the fewest number of people needed to guarantee that at least three people sharefirst and last names beginning with the same letters?d) What is the fewest number of people needed to guarantee that at least three people sharefirst, middle, and last names beginning with the same letters?(Assume that everyone hasfirst , middle, and last names.)

Red Or White, It’s Your Joyce.10. To win a math contest, Joyce must determine how many marbles are in a box. She is toldthat there are 3 identical red marbles and some number of identical white marbles in thebox. She is also told that there are 35 distinguishable permutations of the marbles. So howmany marbles are in the box?{Hint: The number of distinguishable permutations is( R W )! , and we know thatR! W !R 3 .}Don’t Get Punched Out At The Motel.11. A national motel chain has replaced the key lock for each room with a key card system. Adoor is unlocked by inserting a plastic card into a slot above the door knob. Each key’sunique identity is determined by a grid of 63 cells, each of which is either solid or 495051525354555657585960616263a) Determine the number of different key cards possible.b) How many are possible if each key card must have at least one punched cell?

Too Many Officers And Not Enough Enlisted.12. A president, treasurer, and secretary, all different, are to be chosen from a club consisting of10 people(A, B, C, D, E, F, G, H, I, J). How many different choices of officers are possibleifa) there are no restrictions?b) A and B will not serve together?{Hint: Some selections will have only B, some only A, and some won’t have either.}c) C and D will serve together or not at all?{Hint: Some selections will have C and D, and some won’t have either.}d) E must be an officer?{Hint: E has to be one of the officers selected.}e) F will only serve if she is president?{Hint: Some selections will have F as president, and some won’t have F as an officer.}Together, Again!13. A library shelf contains seven books. Three books are math books and four books arescience books. In how many different ways can the seven books be arranged on the shelf sothat all the math books will be together?The Deadly Sin Of Seven.14. Find the number of positive integers less than 100,000 that contain at least one digit of 7.{Hint: How many positive integers are less than 100,000? How many of them don’t have adigit of 7?}

The A, B, C, And D Of Education.15. The results of a survey were the following:12 students take art, 20 take biology, 20 take chemistry, 8 take drama, 5 take art andbiology, 7 take art and chemistry, 4 take art and drama, 16 take biology and chemistry, 4take biology and drama, 3 take chemistry and drama, 3 take art, biology, and chemistry, 2take art, biology, and drama, 2 take biology, chemistry, and drama, 3 take art, chemistry,and drama, 2 take all four, 71 take none of the fourChemistryBiologyDramaArtUa) How many students participated in the survey?b) How many take exactly one class?c) How many take exactly two classes?d) How many take exactly three classes?e) How many take two or more classes?Distinctly Odd, Or Oddly Distinct?16. a) How many whole numbers between 1000 and 9999 have distinct digits?b) Of these, how many are odd numbers?

A Real Noreaster.17. Ms. Jones likes to take a different route to work every day. She will quit her job the day shehas to repeat her route. Her home and work are pictured in the grid of streets below. If shenever backtracks(she only travels north or east), how many days will she work at this job?WorkHomeWorkHome{Hint: Each trip can be thought of as a permutation of a word with 5 E’s and 5 N’s.}“No Orange For You!” Said The Fruit Nazi.18. A father has 5 distinct oranges which he gives to his 8 sons so that each son either receivesone orange or none. How many different ways can he do this?{Hint: Use the formula for permutations with duplicates for 5 different oranges and 3identical non-oranges, and use the position of the orange or non-orange as the sonwho gets that result.}

A Language Barrier?19. In a room there is a group of people in which each person knows at least one of threelanguages: English, German, and French. Six know English, six know German, and sevenknow French. Four know English and German. Three know German and French. Twoknow French and English. One person knows all three languages.a) How many people are in the room?b) How many know only English?c) How many know exactly two languages?d) How many know at least two languages?{Hint: Make a Venn diagram.}One To A Million, Or A Million To One?20. The sum of all the digits in the numbers 1 to 100 can be calculated as follows:The only 3-digit number is 100, and it contributes 1 to the digit sum. If we use themultiplication principle to count the 2-digit numbers, we get1010Tens digit Ones digitSo there are 100 other 2-digit numbers if we include 00, and it doesn’t affect the digit sum.Among the ones digits are 10 zeros, 10 ones, 10 twos, 10 threes, 10 fours, 10 fives, 10sixes, 10 sevens, 10 eights, and 10 nines. This gives a digit sum of 45 times 10. The sameis true of the tens digits, so the digit sum is 45 times 20 plus the additional 1 from the 100leading to a total of 901.a) Find the sum of all the digits in the numbers 1 to 1,000.b) Find the sum of all the digits in the numbers 1 to 10,000.c) Find the sum of all the digits in the numbers 1 to 1,000,000.It’s A Monthly Thing.21. a) What is the smallest number of people in a group that will guarantee that at least two ofthe people were born in the same month?b) What is the smallest number of people in a group that will guarantee that at least three ofthe people were born in the same month?

Texas Hold’em.22. In this problem, we’ll determine the number of possible particular 5-card poker hands.Here is a possible decision process for the 5-card poker hand with one pair1312 C34 C2444WhichWhich twoWhich 3Which one Which one Which onekind ofcards ofotherof the firstof theof the thirdpair?this kind?kinds?kind?second kind?kind?So there are 13 4 C2 12 C3 4 4 4 1,098,240 different two-of-a-kind 5-card poker hands.a) See if you can do the same thing to find the number of different three-of-a-kind hands:Which kind Which three Which 2 Which one Which oneof three-of- cards of thisotherof the firstof thea-kind?kind?kinds?kind?second kind?b) See if you can do the same thing to find the number of different four-of-a-kind hands:Which kind ofWhich other kinds? Which one of thefour-of-a-kind?other kind?The number of different flushes, i.e. five cards of the same suit, but not in orderFirst we’ll count the number of different hands with 5 cards of the same suit:413 C5Which suit? Which 5 cards?Then we’ll subtract the number of hands with 5 cards of the same suit that are in order(thesewould be straight flushes):410Which kind of cardWhich suit?starts the straight flush?So we get 4 13 C5 4 10 5,108 different 5-card poker hands which are flushes.c) See if you can do something similar to find the number of straights, i.e. 5 cards in a row,but not all of the same suit.First we’ll count the number of different hands with 5 cards in a row:Which kind WhichWhich suitWhichWhichWhichof cardsuit forfor thesuit forsuit forsuit forstarts thethe firstsecondthe third the fourth the fifthstraight?card?card?card?card?card?Then we’ll subtract the number of 5-card hands in order of the same suit(straight flushes):

You have learned that the number of permutations of n distinct objects is n!. For instance if youwanted to seat three people along one side of a rectangular table, the number of possiblearrangements is 3!. However, if the three people are to be seated around a circular table, thenumber of possible arrangements is only 2!. Let’s see why: If the people are labeled A, B, andC, the two arrangements look like the following:ABACCBAt first, it might seem that there should be 3! 6 different arrangements, like the following:ABACCBBAC(1)(2)(3)BCCCA(4)ABBA(6)(5)But, if you look closely, you’ll see that arrangements (1), (4), and (5) are identical, each is just arotation of the other. The same is true of (2), (3), and (6).

Knights Of The Circular Table And The Venerable Bead.23. a) Find a formula for the number of different ways that n people(or objects) can be seated(orplaced) around a circular table.{Hint: Start with n!, but divide it by the number of rotations that can be made thatgenerate equivalent arrangements.}b) Use the previous formula to find the number of different arrangements of 12 peoplearound a circular table.c) Use the previous formula to find the number of different necklaces that use 10 differentcolored beads.d) Modify the previous formula to find the number of different necklaces that use 20 beadswith 5 red, 4 blue, 8 green, and 3 yellow.{Hint: Modify an idea from permutations of non-distinguishable objects.}Just Be A Sport.24. Thirty-one students participate in baseball, soccer, and tennis. Some play only one sport,some play two sports, and a few play all three. The results are:19 play baseball16 play soccer17 play tennis9 play baseball and soccer10 play soccer and tennis8 play baseball and tennis6 play all three sportsa) How many students participate in only one sport?b) How many students participate in exactly two sports?

Put Up Your Marbles And Box.25. a) Find the number of ways that seven red marbles and eight white marbles can be placedinto 3 boxes if each box contains at least one of each color.b) Find the number of ways that seven red marbles and eight white marbles can be placedinto 3 boxes if some of the boxes might not have each color or may be empty.{Hint: If we assume that each box receives at least one red then we’ll decide how manyeach box gets by choosing 2 spaces from the 6 spaces between the 7 red marbles:Box # 1gets 1 redmarbleBox # 2gets 3 redmarblesBox # 3gets 3 redmarblesSo if each must box gets at least one, there are 7 C2 21 different ways that the 7 redmarbles could have been distributed into the 3 boxes. To allow for the possibility thatone or more boxes don’t get any red marbles, we’ll pretend that there are actually 10 redmarbles for the 3 boxes.Box # 1gets 2 redmarblesBox # 2gets 2 redmarbleBox # 3gets 7 redmarblesFrom the 9 spaces available, we’ll select 2. If we subtract 1 from each number of redmarbles assigned to each box, we’ll have a way that the boxes could contain all 7 redmarbles even if some don’t have any.Box # 1gets 1 redmarbleBox # 2gets no redmarblesBox # 3gets 6 redmarbles}

It’s As Easy As ABCDEFG.26. Find the number of permutations of ABCDEFG that contain the following:a) the sequence ABC{Hint: They would look like one of the following:ABCABCABCABCABC.}b) the sequences AB, CD, and EF, but not necessarily in this order.{Hint: Treat each pair of letters as a single unit, and decide the position of G. Forexample,ABCDEFGABCDGEFABGCDEFGABCDEF.}c) the sequences AB, BC, and EF, but not necessarily in this order.Have A Seat!27. In a classroom, there are 28 chairs. If 26 students are to be seated in the classroom, howmany different ways can this be done?{Hint: Rather than assign students to seats, assign seats to students.}

Do College Students Still Read?28. A survey of 100 college students revealed the following results:40 read Time Magazine30 read Newsweek Magazine25 read U.S. News and World Report Magazine15 read Time and Newsweek Magazines12 read Time and U.S. News and World Report Magazines10 read Newsweek and U.S. News and World Report Magazines4 read all three magazinesa) How many read at least one magazine?b) How many read exactly one magazine?c) How many read exactly two magazines?d) How many read none of these magazines?{Hint: Make a Venn diagram.}Well Jenny, It Can’t Be 867-5309!29. John is having trouble remembering his girlfriend Jenny’s 7-digit phone number. Heremembers that the first four digits consist of one 1, one 2, and two 3s. He also remembersthat the fifth digit is either a 4 or 5. While he has no memory of the sixth digit, heremembers that the seventh digit is 9 minus the sixth digit. If this is all the information hehas, how many possible phone numbers are there?{Hint:How many for the first4?How many here? How manyhere?}Don’t Be A Sloth-Two Or Three Toed.30. a) How many whole numbers less than 1,000 contain no digits of 3 but at least one digit of2?{Hint: How many have no 3’s? How many have no 2’s?}b) How many whole numbers less than 1,000,000 contain no digits of 3 but at least onedigit of 2?

A library shelf contains seven books. Three books are math books and four books are science books. In how many different ways can the seven books be arranged on the shelf so that all the math books will be together? The Deadly Sin Of Seven. 14. Find the number of positive integers less than 100,000 that contain at least one digit of 7.