Bridge Course - Maa.ac.in

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Bridge Course (REVISED) for Std – 8th Mathematics PromoterPublisher Motivation : Department of School Education, Government of Maharashtra.: State Council of Educational Research and Training, Maharashtra, Pune: Shri.Ranjeetsingh Deol, (I.A.S.)Hon’ble Secretary, Department of School Education and Sports, Maharashtra.Guider: Shri.Suraj Mandhare, (I.A.S.)Hon’ble Commissioner (Education), Maharashtra.Shri.Kailas Pagare (I.A.S.)Hon’ble State Project Director Maharashtra Prathmik ShikshanParishad,Mumbai:EditorShri. M.Devender Singh (I.A.S)Director, State Council of Educational Research and Training, Maharashtra,PuneCo-Editor : Shri. Ramakant KathmoreJoint -Director, State Council of Educational Research and Training,Maharashtra, PuneExecutive Editor : Shri.Vikas Garad,Principal, State Council of Educational Research and TrainingMaharashtra, Pune.Smt.Rantprabha BhaleraoSenior Lecturer, Department of Mathematics, SCERT, Pune.Smt.Vrushali GaikwadLecturer, Department of Mathematics, SCERT, PuneEditing Support: Smt.Vaishali Gadhave and Smt. Bhakti JoshiSubject Assistant, Department of Mathematics, SCERT, PuneProduction member:1 . Dr. Vaishali Jahagirdar2.Senior Lecturer ,DIET,Aurangabad.Mr. Atul Kulkarni Asst.Teacher Z.P.School Sindagi ,Tal-Kalmnuri,Dist.Hingoli.3. Mr. Subhash Marwade Z.P.School & Jr.College Aamgaon Dist- Gondia.Bridge course Translator :1. Mr. Sachin Batwal Guru Nanak Highschool & Jr.College Pune

Instructions for StudentsDear students, due to pandemic situation in the last academic year youcontinuedyour learning and education through online and in various digital modes. This BridgeCourse has been prepared for you with the objective of reviewing the previous year'ssyllabus at the beginning of the present academic year and helping you to prepare for thisyear's syllabus.1. The bridge course lasts for a total of 30 days and consists of tests after a certainperiod of time.2. The bridge course will help you to understand exactly what you have learned in theprevious academic year and to understand the curriculum for the next class.3. This bridge course should be studied on a day-to-day basis.4. It consists of day-to-day worksheets. You are expected to solve the worksheet onyour own as per the given plan.5. Seek the help of a teacher, parent or siblings if you have difficulty solving theworksheet.6. The video links are provided to better understand the text and activities given ineach worksheet for reference, try to understand the concept using them.7. Solve the tests provided along with as planned.8. Get it checked with the teacher after completing the test.9. Seek the help of teachers, parents or siblings to understand the part that is notunderstood or seems difficult.Best wishes to you all for the successful completion of this Bridge Course!Instructions for Teachers, Parents and FacilitatorsAs we all are very well aware about the fact that due to pandemic situation, theschools were formally closed during the last academic year and the actual classroom teachingand learning could not take place. There is uncertainty even today as to when schools willrestart in the coming academic year. On this background various efforts have been made bythe government in the last academic year to impart education to the students through onlinemode. Accordingly, the Bridge Course has been prepared with thereviewing the studies done by the students in the previous academicto learn the curriculum of the present class in this academic year.dualobjectiveofyear and helping them

1. The bridge course lasts for a total of 30 days (Excluding holidays) and consists of tests.Pre-test is given with this set and posttest will be published before test schedule on website.2. The bridge course is based on the syllabus of previous class and is a link betweenthe syllabi of previous and the current class.3. This bridge course has been prepared class wise and subject wise. It is related to thelearning outcomes and basic competencies of the previous class’ textbook and is based on itscomponents.4. The bridge course includes component and sub-component wise worksheets. Theseworksheets are generally based on learning outcomes and basic competencies.5. The structure of the worksheet is generally as follows.Part One - Learning Outcomes/Competency Statements.Part Two – explaning concept.Part three - Solved Activity/ DemoPart Four - PracticePart Five – little help, DIKSHA Video Link/E-Content/QR CodePart Six- My Take Away/ Today I Learnt6. This bridge course will be very important from the point of view to revise andreinforce the learning of the students from the previous class and pave the way to make theirlearning happen in the next class.7. Teachers/parents and facilitators should help their children to complete this bridgecourse as per day wise plan.8. Teachers/parents and facilitators should pay attention to the fact that the student willsolve each worksheet on his/her own, help them where necessary.9. The teacher should conduct the tests from the students after the stipulated timeperiod, assess the test papers and keep a record of the same.10. Having checked the test papers, teachers should provide additional supplementaryhelp to the students who are lagged behind.Best wishes to all the children for the successful completion of this Bridge Course!

State Council of Education Research and training Maharashtra PuneINDEXBridge Course –Standard -8thSr.No. 93030TopicAngle bisector & perpendicular bisector of trianglesGeometrical construction - congruencyProduct of IntegersDivision of IntegersHCF & LCMAngles Interior exteriorPairs of anglesProperties of opposite & external anglesIntroduction of rational numbersAddition &subtraction of rational numbersProduct of rational numbersIntroduction of indicesRules of indicesIntroduction of algebric expressionAddition & subtraction of algebric expressioProduct of algebric expressiDirect proportionInverse proportionBankingCompound interestCircumference & diameter of a circle relationArc of a circlePaythagoras Theorem and it’s TripletsPerimeter of rectangle & squareArea of rectangle & squareArea of right angled trianglesSurface area of cuboid & cubeSquare of BinomialFactorization of Algebric ExpressionAverageName of the Student: ----Name of the School and Address: ------------------------------------

Area :knowledge of number and operation on numbersSubunit – product of integerUnit – product and division of numbersDay - Thirdknowledge cornerScene Ajay & Vijay are two friends Ajay needs Rs 20 so he borrow Rs.20from Vijay.Vijay give him Rs.20 After some time Ajay again borrrow Rs.20from Vijay.So twotimes Vijay give him Rs.20 First time Ajay borrow amount from Vijay Second time Ajay borrow amount from Vijay Total borrowed Amount(-40 Rs. )(-20Rs. )(-20Rs. )Hence (-20)&(-20) becomes (-40)(-20 ) (-20) -40two times-20 became -402 x (-20) -40think thatwhy Rs.20 written as(-20)? See product of integer on number line See some example below product of integer on number line2 times (-3)get -63 times (-2) we get -62 times (-3)get -6&opposite numberof -6 is 6I understood1) Product of two positive number is always positive2) Product of one positive & one negative number is always negative3) Product of two negative number is positive

practice corner – Solve the following examples. & show product on integer number line1)2)3) Let’s Solve - Solve the following example using positive & negative sign at correct places1) In kabaddi match when match is lost, then each lost loss of 5 marks loss & when match is winthen gain of 10 marks. One team lost 3 match & gain 4 match then what is total marks of thatteam2) One submarine go from sea surface to deep in sea each minute 50 meter.Determine in halfan hour how meter it will go in deep sea?

Quick HelpDiksha app linkhttps://diksha.gov.in/play/collection/do 312528209295843328153323?contentId do 3130003196883763201131\

Area – knowledge and operation on numbersSubunit – division of integerUnit – product and division of integerDay - FourthConcept CornerLet’s play a game – for positive integer we take yellow circle & for negative integer red circle and asgiven in the instruction divide equally in positive integer & ngative integers.positive integernegative integer1)we divide equaly in two parts then what happen ?each part having two positive . that is2)we divide equaly in two parts then what happen ?each part having two negative . that is Now if we take division of integer then what answer we get1)(2)1) now we divide negative integer by negative integer then what answer we get. why answer is Positive Remember that on number line we take productof ttwo ngative number is written as opposite number of answer. because negative meansopposite number. we can’t make a negative group of any number? Hence making positivegroup & then write opposite number of answer2) In above example We not make -3 group of – 12 but make 3 group so that each groupcontain -4 then we write opposite number of -4 is 4 hHence ngative integer divide bynegative integer then answer is positiveI understood4) Division of two positive integer is positive5) One Positive & One negative integer numbers product is negative6) Division of two negative integer is positivePractice CornerSolve the following division If answer is positive then integer write that number of yellow cicrcle ingiven box if answer is negative answer then write red circle in given box

Solve Challanging Question - By writing positive & negative sign at correct places1) 8 friends get a loss in business is Rs. 5600 if loss each friend is equal then what is loss of each Quick Help Ebalbharti 7 th maths text book link - https://cart.ebalbharati.in/BalBooks/ebook.aspx Diksha app link – video पाहा https://diksha.gov.in/play/collection/do 312528209295843328153323?contentId do3130003201933803521144

Area – knowledge and operation on numbersSub unit : HCFUnit – HCF & LCMDay– FifthConcept CornerSaee has 16 blue diamond & 8 red diamonds She want todivide both diamonds ineual group so thatshe carefully divide no diamond remains we help her to do thisblue diamonds – 16 & red diamonds – 8 we grouped 16 diamonds as below so that no diamond be remains – 1,2,4,8,16 we grouped 8 diamonds as below so that no diamond be remains – 1,2,4,8 Common group of 16 & 8 are – 1,2,4,8 among this common group gretest group is – 8hiding maths – 16 & 8 having common greatest factor is 8 hence HCF is 8now we determine HCF of 16 & 8 by prime factor method 16 2x2x2x2factors of 8 are –product of common factor of 8& 6 hence HCF of 16 & 8 is 8.I Understood7) Product of pair of prime factor of two or more number is HCF of thatnumbers8) Greatest common factor of given number is HCF of that numbers.9) HCF can be determine by list method prime factor method ordivision method.10) HCF of two or more prime number is always 111) HCF is not equal to 0 & not more than given numbers Practice Corner :See following Example1) HCF of 12 & 18 can be determined by list method as following.Factor of12 – 1,2,3,4,6,12Factor of 18– 1,2,3,6,9,18Common factor of 12&18– 1,2,3,6.Greatest factor – 6Hence HCF of 12 & 18 is 6.2) HCF of 9 & 15 by using prime factor as following .Prime factor of 9 –Prime factor of 15 –Common factor of 9 & 15 – 3Greatest factor– 3HCF of 9 & 15 is 3.

Let’s Solve :Find HCF by both method list method & prime factor method and compare answer .HCF of 10 & 15 – by list metodHCF of 10 & 15– by using prime factor metodusing productfactor of 10-Prime factor of 10-Factor of 15 -Prime factor of 15-Common factor-Common factor-Greatest factor in common factor -Greatest common factor -HCF of 10& 15HCF of 10&15 - Is answer is same by both method tick mark on correct option yes / no Quick HeipDiksha app link – To find HCF click the linkhttps://diksha.gov.in/play/collection/do 312528209295843328153323?contentId do3130140123786772481242

Unit – HCF & LCMSubunit – LCM Concept CornerScene – Pankaj go every 6th day to swimming & every 4th day to tabla class . Today he go to bothlaces then again what day he go to both places.See any thing remainde you ? You also take help ofcalender again how can solve this?any other method? Day for swimming are 6 th, 12th, 18th,.and so ontable of 6 – 6,12, 18, 24, For tabla class days 4th,8th,12th,16th,.and so onTable of 4 – 4, 8, 12, 16, 24, 6See care fully pankaj go to both swimming & tabla class on same day which are12,24.and like that Which is first day for both activity exactly 12th day 12 is smallest & same number which is in both table 4 & 6 12 is a smallest number which is divisible by both 4& 6 Hence least common multiple LCM of 4& 6 is 12 . I understood Least multiple of two or mote number is LCM of that given numbers. Given numbets wrtten in their multiple or their table and then their smallest common multiple iscalled LCM Two or more than two numbers having LCM is always greater than that numbers List method Facorization method or division metod are used to determine LCM Given two or more numbers if Greater number is divisible by smaller number then greaternumber is LCMfor example 4,12,36 then 36 is divisible by all 4,12,36 then LCM is 36.LCM product of common,& uncommon factors Practice cornerNow we determine LCM of 4& 9 by using list method ,prime factor method & division method& then we see answer by all method !List Method – Table of 4 – 4, 8,12, 16, 20, 24, 28, 32, 36, 40, 44, 48,52,56,60,64,68,72 Table of 9 – 9,18, 27, 36, 45, 54, 63, 72, 81,90, 99,--Common numbers of 4th & 9 th table – 36, 72, least common multiple is 36. hence LCM of 4 & 9 is 36.

Prime factor method –prime factors of 4 , Prmime factor of 9 Common factor of prime factor of 4 & 9 has no common factors.Produc of uncommon factors of 4 & 9 isLCM Product of common prme factors & uncommon prime factorsDivision method – See the adjoining method take a prime factor of 4 & 9 upto 1then take product of common and uncommon factor we get LCM this method isknown as division method Solve this –1) Find LCM of 8&12 by list method2) What is LCM of 3,9,&27 without using factorization -----------3) Find LCM of 5,6&7 by using division method Quick HelpDiksha app link –See video of LCMhttps://diksha.gov.in/play/content/do 31327270197864038416463

I UnderstandPractice

Area – knowledge and operation on numbersSubunit – Introduction of rational numbersUnit – Operation on rational numbersDay - 9thConcept CornerScene: shamal bring a big cake and make ‘Cut into 8 equal part 2 part eat by shamal.Two part eatby her younger brother. 1 part each eat by her mother & father.one part each eat by her grandpa &grandmawe write part of cake eaten by each person mathematicallyEqual part of cake – 8eaten by shamal -Eaten by younger brother -Eaten by mother -Eaten by father -Eaten by grandma-Eaten by grandpa Think & markAt correct place Can we cut a cake in 0 equal parts ?See maths funmeansyes/ nomeans4/0 is not possible as 0 0 not equal 4 That means no number is divided by 0In case of cake we write all numbers in form but we can’t write q 0 We Write 2 in form as Also -5 inform But 2 or -5 cannot be write as 2/0 or -5/0 2is whole number while -5 is integer I understand12) Number which can be written as p/q form & q is not equal to 0 iscalled rational number All natural, whole,integer,decimal numbers canbe written in the form of rational numbers but denominator is not 013) All fractions are rational numbers but all rational numbers may ormaynot be rational numbers Eational numbers are negative or positive. Practice cornerSee these example which are rational numbers .These example are not rational numbers.These example are not fraction, ,,etc., - , 6, 12, -18, 2.1 etcetc.

Let’s SolveNumber12-7/917/08/9-Mark thisRationalat correct places.Not rational Small HelpDiksha app link Rational number video.https://diksha.gov.in/play/content/do 31327270259433472016527FractionNot fraction

Subunit – addition & subtraction of rational numbers Day - 10thConceptCornerScene 1 – Ayush compete journey in two stages He complete 2/6 part journey yesterday & 4/6 partjourney today .So how much part journey completed in two day.!Part of journey by Ayush yesterday 2/6Part of journey by Ayush today 4/6For total journey we adding . Scene 2 - Suraj take 5/2 sugar & Sohel take 5/2 sugar How many Kg sugar they both takeSugar bought by Suraj 5/2 kgSugar bought bySohel 7/3 kgSugar bought by both kgScene3 – Sagar baught gold16/7 gm Sangita baught gold12/5gm How many more gram gold baughtby sangita thn sagarGold baught by saSagar 16/ 7gmGold baught by Sangita 12/5 gmMore gold baught by sangita than Sabgar gm I understood1) When addition or subtraction of rational numbers whose denominator areequal we only add or subtract numerator2) When denominator are different then equal denominator by taking LCM.3) When we add or subtract decimal fraction then adding or subtractinginteger 7 add or subtract fraction by decimal method Practice Corner – Compete following activity.1)2)

Let’s Solve –Solve the following addition / subtraction1) 2) 3) 4) Quick HelpDiksha app link – Addition & subtraction of rational numbershttps://diksha.gov.in/play/collection/do 312528209295843328153323?contentId do 3130003206227312641121

Subunit – product of rational numberDay - 11th Concept Corner 5 times of 3/4 is equal to? for solving this example help of addition & multiplication 5 times of 3/4 hence we take 3/4 five times we write in the form of addition. as Also we write in the form of multiplication – Method by taking multiplication is very easy Now see next example.rational numbers is always negativeIn this example product of negative & positive How can you solve ?. In this example rational numbers multiplications ofnumerator & multiplication of Denominator I understood1) Multiplication of rational number at numerator product of numerator &at Denominator product of denominator2) When product of negative & positive rational numbers we follow rulesof sign3) When division of rational number taking reciprocal of divisor & andthen product4) While division we follow rules of sign same as for integers.𝟏 . What is the answer of this question means that divide 𝟐 in two equal parts byfigure we can observe it clearly. 𝟏𝟐rational number we see1 wholeHalf of half is one fourth h Similarly let’s solve following exampleलक्षात घ्या – Practice Corner–दोन परिमेय संखयांचा भागाकाि कितानापरिमेय संखयेचactivityी गुणाकािव्यस्त संखया घेवनू गुणाकाि केला आहे .Completetheभाजकfollowing1)

2)Let’s Solve –Solve following multiplication & Division1) 𝟏𝟐𝟖2) 𝟗𝟐𝟑𝟕 𝟖 3) What is -5 times of 4/9?4) Divide 2/3 in -1/5 equal parts then each part is Quick helpDiksha app link Video link for multiplication & division of rational number1) https://diksha.gov.in/play/collection/do 312528209295843328153323?contentId do 31300032079723724811002) https://diksha.gov.in/play/collection/do 312528209295843328153323?contentId do 3130007804581642241248

Area – knowledge and operation on numbersSubunit – introduction of indicesUnit – IndicesDay - 12thConcept Corner Let remember Find the following product.1)(2)(3) Check whether your answer is correct or not1)4(2)(3)Very good ! Now we see another method for writing when one number is multiplied by itself Now see understand and write the answer at the blank spacesYou write 4 in the blank spaces correct but why? Because in first place you multiply 2 by two times hence 2 is written on head of 2 multiply 2 by three times hence 3 is written on head of 2 multiply 2 by Four times hence 4 is written on head of 2Yes understood a number is multiply by itself in how many times can be written on head of thatnumber in number 2 is a base & number 3 on head is index in this number 6 is base & 5 is index ,6 is multiply by 6 in 5 times its product form is The number which can be form by base & power is called Indices number I understood A number is multiplied by itself in one or number of times thenthat number of times is called index or power of that numbers Base & index we get indices Index form of numbers means number multiply with itself Practice corner let’s try to understand1)2)3) Try to understand following1)2)

Let’s Solve Write tickmark & crossmark at correct placesnumberfalsetruenumberfalsetrueQuick helpDiksha app link – Index number Videohttps://diksha.gov.in/play/collection/do 312528209295843328153323?contentId do 3130003210636247041101

Area – Number work and operations on numberSubunit – Rules of Indices Unit – IndicesDay - 13thConcept CornerLet's observe the following math fun.𝟑𝟐 𝟑𝟑 𝟑 𝟑 𝟑 𝟑 𝟑 In this example, the number 𝟑𝟐 was initially written as a multiplicationform and the number 𝟑𝟑 was also written as a multiplication form and then the multiplication of all 3’swas presented in one place Now try to write the multiplicative number here as index form !𝟑 𝟑 𝟑 𝟑 𝟑 Make sure that you have written35 in the blank space . Have you done? . Very nice Now itcan be written together as follows.𝟑𝟐 𝟑𝟑 𝟑𝟓 means 𝟑𝟐 𝟑𝟑 𝟑𝟐 𝟑 𝟑𝟓 𝟑𝟓Similarly we can write 𝟑𝟓 𝟑𝟑 𝟑𝟑 𝟑 𝟑 𝟑 𝟑 𝟑𝟑 𝟑 𝟑 𝟑 𝟑 𝟑𝟐 in short 𝟑𝟓 𝟑𝟑 𝟑𝟐Now observe the given pattern and write what number will appear in the blank space. Have you tried? . Write the number that comes in the blank space. The number 1 appears in the blank space. As the index is decreasing by one then itsvalue becoming half of previous one. Here 8, 4 and 2. Thus 2 will be followed by 1. In the case of any other index form of the number you will find the same result. . Now I know The following rules are used to calculate the value of indexnumber . We call them laws of indices : Practice Corner -Study the examples in the table below and write the correct number in the blanks.1) 𝟓𝟒 𝟓𝟑𝟓𝟒 𝟓𝟕2) 𝟗𝟓 𝟗𝟐𝟗𝟓 𝟑3) ( 𝟑𝟒 )𝟓 𝟑𝟒 𝟓 𝟑4) 𝟏𝟐𝟎5) 𝟏𝟏 𝟐𝟏𝟏 𝟐 𝟏𝟏𝟏

Let’s solve1)𝟏𝟑𝟓 𝟏𝟑𝟖-Solve the following examples using laws of indices. 2) ( 𝟒)𝟗 ( 𝟒)𝟒 𝟒3) (𝟒 𝟐 ) 4) 𝟏𝟐𝟑𝟒𝟎 5) 𝟖 𝟑 Quick helpDiksha app link – Laws of Indices – Watch the given video.https://youtu.be/sbftWkb3CmE

Area – AlgebraUnit – Algebraic Expressions and Operations on themSubunit – Algebraic Expressions-IntroductionDay - 14thConcept CornerLet’s recall1. How many mangoes will be 2 mangoes and 3 mangoes together? --- There will be 5 mangoes2. How many fruits will there be with 2 mangoes and 3 chickoos? -There will be 5 fruits.That's right.If we use the letter x for 1 mango, note that 2 mangoes and 3 mangoes together will be 5 mangoes.This can be written as 𝟐𝒙 𝟑𝒙 𝟓𝒙Now let us use the letter x for 1 mango and the letter y for 1 chikoo. because mango and chikoo aredifferent fruits so the letters used for them will also be different. Now let's do addition of 2 mangoesand 3 chickoos as follows. 𝟐𝒙 𝟑𝒚Note that the above addition will not be 5xy. 𝑳𝒆𝒕 𝒖𝒔 𝒄𝒂𝒍𝒍 𝒕𝒉𝒆 𝒆𝒙𝒑𝒓𝒆𝒔𝒔𝒊𝒐𝒏 𝒇𝒐𝒓𝒎𝒆𝒅 𝒃𝒚 𝒏𝒖𝒎𝒃𝒆𝒓𝒔 𝒂𝒏𝒅 𝒍𝒆𝒕𝒕𝒆𝒓𝒔 𝟐𝒙 𝒂𝒏𝒅 𝟑𝒚 𝒂𝒔 𝒕𝒉𝒆𝒂𝒍𝒈𝒆𝒃𝒓𝒂𝒊𝒄 𝒆𝒙𝒑𝒓𝒆𝒔𝒔𝒊𝒐𝒏′. 𝑯𝒆𝒓𝒆 𝒕𝒉𝒆 𝒏𝒖𝒎𝒃𝒆𝒓𝒔 𝟐 𝒂𝒏𝒅 𝟑 𝒂𝒓𝒆 𝒄𝒐𝒆𝒇𝒇𝒊𝒄𝒊𝒆𝒏𝒕𝒔 𝒂𝒏𝒅 𝒕𝒉𝒆𝒍𝒆𝒕𝒕𝒆𝒓𝒔 𝒙, 𝒚 𝒂𝒓𝒆 𝒄𝒂𝒍𝒍𝒆𝒅 𝒗𝒂𝒓𝒊𝒂𝒃𝒍𝒆𝒔. Now I know!1) The term formed after multiplying numbers by letters is calledalgebraic term.2) Numbers are called coefficients and letters are called variables.3) Expressions are named after the number of terms they have.Expressions with one term are called monomials, those with twoterms, binomials, with three terms, trinomials and if they have morethan three terms, they are called polynomials4) Terms which have the same variables with the same powers are called‘like terms’5)6)7) Practice Corner8) Given algebraic9)expressions are monomials: - 𝟑𝒙 , 𝟒𝒚, 𝟖𝒛𝟐 etc. Given algebraic10)expressions are binomials: 𝟑𝒙 𝟐𝒚, 𝟓𝒛 𝟗𝒑 etc.11)‘like terms’. Given algebraic expressionsare trinomial: 𝟑𝒙 𝟐𝒚 𝟗𝒛, 𝟓𝒛 𝟗𝒑 𝟕𝒒 etc. The terms in the given pair are the like terms.𝟒𝒙𝟐 𝒚 व 𝟗𝒙𝟐 𝒚 , 𝟑𝒛 व 𝟓𝒛 etc.Note that all the above expressions are also polynomial .Let’s solve –Mark in front of the type of correct polynomial in the following table.Algebraic expression𝟒𝒙𝒚𝒛𝟔𝒚 𝟗𝒛𝟖𝒂 𝟗𝒃 𝟕𝒄Monomialbinomialtrinomial

Write any like term for the following algebraic term. 1) 𝟒𝒙𝒚 Quick help(2) 𝟐𝒙𝟑 𝒚 (3) 𝟗𝒑𝒒𝟑 𝒓 Diksha app link – Watch the video on algebraic expression .https://youtu.be/ffLLmV4mZwU

Area – AlgebraUnit – Algebraic Expressions and Operations on themSubunit – Addition & Subtraction of Algebraic ExpressionsDay - 15th Concept Corner 3 Chikoo and 5 Chikoo together make 8 Chikoos. Let's solve this additionusing the following methods. We will use the letter x for a chikoo.𝟑𝒙 𝟓𝒙 𝟖𝒙 After selling 3 dozen mangoes out of 10 dozen mangoes,7 dozen mangoesremains, using the variable y for 1 dozen mangoes we can write this subtractionas follows.𝟏𝟎𝒚 𝟑𝒚 𝟕𝒚 Let us write the total number of 2 chikoo and 3 mangoes using the letter x forchikoo and the letter y for mango.2x 3y Note that : Here the addition will not be 5xy . Now I know! In algebraic expressions additions and subtractions aremade only of like terms of expressions. When there are no like terms, the addition or subtractionis written using variables as it is . Practice Corner : Study examples of addition and subtraction in the following table .Let’s solve -𝟒𝒙𝒚 𝟗𝒙𝒚 𝟏𝟑𝒙𝒚𝟒𝒑 𝟑𝒑 𝟏𝒑Solve the examples of addition and subtraction in the following table .𝟕𝒑𝒒𝒓 𝟐𝒑𝒒𝒓 𝟏𝟐𝒛 𝟏𝟎𝒛𝟖𝒙 𝟑𝒚𝟐𝟕𝒎𝒏 𝟐𝟎𝒎 Quick helpDiksha app link – Addition and subtraction of algebraic expressions - watch the video .https://youtu.be/kuntXMSMYrE

Area – AlgebraUnit – Algebraic Expressions and Operations on themSubunit – Multiplication of Algebraic ExpressionsDay - 16th Concept CornerLet’s recall. –1) Multiplication is repeated addition of the same number or expression.2) According to the laws of indices ,when the indices with the same base aremultiplied then we add the indices in the resultant product and the indicesare subtracted in division. 2 times 2x ? For this we will add it up twice and see what the answer is.𝟐𝒙 𝟐𝒙 𝟐 𝒕𝒊𝒎𝒆𝒔 𝟐 𝒙 𝟒𝒙 Now if we take 3xy ; 4 times, you will have noticed that 12xy will come.From this,𝟒 𝟑𝒙𝒚 𝟏𝟐𝒙𝒚 𝟐𝒙 𝒕𝒊𝒎𝒆𝒔 𝟒𝒙 𝒘𝒊𝒍𝒍 𝒃𝒆 𝒎𝒖𝒍𝒕𝒊𝒑𝒍𝒊𝒆𝒅 𝒖𝒔𝒊𝒏𝒈 𝒕𝒉𝒆 𝒍𝒂𝒘𝒔 𝒐𝒇 𝒊𝒏𝒅𝒊𝒄𝒆𝒔𝟐𝒙 𝟒𝒙 𝟐 𝟒 𝒙 𝒙 𝟖𝒙𝟐 Now let's see how multiplication will work if there are different variables.Such as 𝟑𝒙𝒚 𝟐𝒑𝒒 𝟑 𝟐 𝒙𝒚 𝒑𝒒 𝟔𝒙𝒚𝒑𝒒 Now I know!1) While multiplying algebraic expressions, multiply thecoefficients by the coefficients and multiply the variablesby the variables.2) If there are variables, multiply the indices by using therule of multiplication of index.3) If there are no like terms, in multiplication they all writethe same in multiplication form. Practice cornerStudy the following Products.(2) 𝟓𝒙 𝟔𝒙𝒚 𝟑𝟎𝒙𝟐 𝒚(1) 𝟓 𝟔𝒙𝒚 𝟑𝟎𝒙𝒚 Let’s Solve blanks.(3) 𝟑𝒙𝒛 𝟒𝒚 𝟏𝟐𝒙𝒚𝒛Study the following multiplication and write the correct number in the(1) 𝟏𝟐 𝟑𝒙 𝟑𝟔(2) 𝟒𝒙 𝟐𝒙 𝟖

(3) 𝟓𝒙𝒚 ( 𝟐)𝒛 𝒙𝒚𝒛(4)𝟏𝟎𝟎𝒙𝟑 𝟐𝒙𝟑 𝒚 𝟐𝟎𝟎(5)(5) 𝟏𝟎𝒍𝒎𝒏 𝟑𝒍𝒎 (6)(6) 𝟗𝒚 𝟑𝒙𝒚 𝟐𝟕 Quick HelpDiksha app link – Video Link for : Multiplication of Algebraic Expressionshttps://youtu.be/YqnsUf40gNI

Area – Applied mathematicsUnit – Direct Proportion and Inverse ProportionSubunit – Direct Proportion and Inverse ProportionDay - 17th & 18thConcept CornerEvent - Children of Mangal Society are going from house to house on the occasion ofGaneshotsav and collecting donations. The number of houses they visited and the donationreceived from each house are given in the table below. Let's understand that.Number of houses visitedDonation from each household (in rupees)23005750101500Observe the above table carefully , write the correct answers to the following questions.1. The amount of donation increases / decreases as the number of houses increases.My Answer - ---2. How much is the donation from one house?My Answer - Let's check the answers given are correct or not .1. The amount of donation increases / decreases as the number of houses increases.My answer - increases.2. How much is a donation from one house fee?My answer - Rs. 1502. The secrete /hidden mathematics behind this –The ratio of the number of houses visited and the donaton collected from each house 𝒏𝒖𝒎𝒃𝒆𝒓 𝒐𝒇 ��𝒏 ��𝟏 𝟑𝟎𝟎 𝟕𝟓𝟎 𝟏𝟓𝟎𝟎 𝟏𝟓𝟎That is, the ratio of the number of houses to each donation collected is constant. which is ,1:150 Now look at the example in the table below.Number of pages read per dayThe days it takes to finish reading a book204010805160Got it? Let's find , What is the total number of pages in the book to read the book completely?Exactly 800The secrete /hidden mathematics behind this – As the number of pages read per day decreases, the number of days it takes to finishreading a book increases. 𝑵𝒖𝒎𝒃𝒆𝒓 𝒐𝒇 𝒑𝒂𝒈𝒆𝒔 𝒓𝒆𝒂𝒅 𝒑𝒆𝒓 𝒅𝒂𝒚 𝒅𝒂𝒚𝒔 𝒓𝒆𝒒𝒖𝒊𝒓𝒆𝒅 𝟐𝟎 𝟒𝟎 𝟏𝟎 𝟖𝟎 𝟓 𝟏𝟔𝟎 𝟖𝟎𝟎 That is, the product of the number of pages and the number of days required is constant.

1.2.3.4. Now I knowAn increase or decrease in one quantity increases or decreases in another quantitybased on it, Such a proportion is called as direct proportion.If the given quantities are in direct proportion then their ratio is always constant.An increase in one quantity leads to a decrease in another quantity based on it or adecrease in one quantity leads to an increase in another quantity . Such a proportionis called inverse proportion.If the given quantities are inverse proportion, then their product is always constant. Practice Corner

Part three - Solved Activity/ Demo Part Four - Practice Part Five - little help, DIKSHA Video Link/E-Content/QR Code . In kabaddi match when match is lost, then each lost loss of 5 marks loss & when match is win then gain of 10 marks. One team lost 3 match & gain 4 match then what is total marks of that . 2) HCF of 9 & 15 by using prime .