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NATIONALSENIOR CERTIFICATEGRADE 11PHYSICAL SCIENCES: PHYSICS (P1)NOVEMBER 2019MARKS: 150TIME: 3 hoursThis question paper consists of 14 pages and 2 data sheets.Copyright reservedPlease turn over
Physical Sciences/P12CAPS – Grade 11DBE/November 2019INSTRUCTIONS AND INFORMATION1.Write your name and class (e.g. 11A) in the appropriate spaces on theANSWER BOOK.2.This question paper consists of TEN questions. Answer ALL the questions inthe ANSWER BOOK.3.Start EACH question on a NEW page in the ANSWER BOOK.4.Number the answers correctly according to the numbering system used in thisquestion paper.5.Leave ONE line between two subquestions, e.g. between QUESTION 2.1 andQUESTION 2.2.6.You may use a non-programmable calculator.7.You may use appropriate mathematical instruments.8.You are advised to use the attached DATA SHEETS.9.Show ALL formulae and substitutions in ALL calculations.10.Round off your FINAL numerical answers to a minimum of TWO decimalplaces.11.Give brief motivations, discussions, etc. where required.12.Write neatly and legibly.Copyright reservedPlease turn over
DBE/November 2019QUESTION 1: MULTIPLE-CHOICE QUESTIONSVarious options are provided as possible answers to the following questions. Choosethe answer and write only the letter (A–D) next to the question numbers (1.1 to 1.10) inthe ANSWER BOOK, e.g. 1.11 E. Each question has only ONE correct answer.1.1Two forces, F1 and F2, act simultaneously at a point in the directions as shownin the sketch below.F1F2Which ONE of the following represents the resultant of the two forces?ABCD(2)Copyright reservedPlease turn over
Physical Sciences/P11.24CAPS – Grade 11DBE/November 2019Which ONE of the following statements regarding inertia of an object isCORRECT?The inertia of an object 1.3Ais greater if its mass is smaller.Bincreases as the applied force on the object increases.Cis the resistance to any change in its state of motion.Dincreases as the frictional force on the object increases.Which ONE of the following statements regarding the frictional force acting onan object is CORRECT?The frictional force is Adirectly proportional to the normal force.Bdependent on the velocity of the motion.C independent of the type of surface.D1.4equal to the weight of the object.(2)Which ONE of the following graphs represents the relationship betweenacceleration and mass of an object if a constant net force acts on it?ABa(m·s-2)a(m·s-2)m (kg)Cm (kg)Da(m·s-2)a(m·s-2)m (kg)Copyright reservedm (kg)Please turn over(2)
DBE/November 20191.51.61.7According to Newton's Third Law of Motion, the reaction force to the weight ofa book lying on a table is the Anormal force.Bforce of the book on Earth.Cforce of Earth on the book.Dforce of the book on the table.(2)The measure of the refractive power of a medium is called the Arefractive index.Boptical density.Crefraction.Dspeed of light in the medium.A central bright band is observed when light of wavelength λ travels through aslit of width w.Light of wavelength 2λ is now used. A central bright band of the SAMEbroadness will be produced if the slit width used is 1.8AwB½wC¼wD2w(2)The electric field at a point is defined as Athe region in space where an electric charge experiences anelectrostatic force.Bthe electrostatic force per unit positive charge.Cdirectly proportional to the product of the charges.Dthe direction that a negative test charge would move.Copyright reserved(2)Please turn over
6CAPS – Grade 11Physical Sciences/P11.9DBE/November 2019The diagram below shows a coil and a magnet with a pole, P. A magneticfield is induced in the coil due to the motion of the magnet.XPWhich ONE of the following combinations will result in an induced magneticfield with a NORTH POLE at point X?DIRECTION OF MOTIONOF MAGNETInto the coilUp and down inside the coilInto the coilUp and down inside the coilABCD1.10POLARITY OF PNorthNorthSouthSouth(2)The cell in the circuit below delivers a potential difference of 1,5 V. The bulbsare identical and the current in the circuit is 0,2 A.The energy, in joule, transferred by ONE of the bulbs in one minute is A1,5 0,2 1B1,5 0,2 60C0,75 0,2 1D0,75 0,2 60Copyright reserved(2)[20]Please turn over
DBE/November 2019QUESTION 2 (Start on a new page.)A billboard, mass 15 kg, is suspended from a roof by means of a light inextensiblestring. Force F pulls the billboard sideways, as shown in the diagram below.40 F15 kgWhen the angle between the roof and the string is 40 , a closed vector diagram isobtained for all the forces acting on the billboard.2.1What deduction can be made when the forces acting on an object forms aclosed vector diagram?(2)2.2Calculate the weight of the billboard.(2)2.3Draw a labelled closed vector diagram of ALL the forces acting on thebillboard. Indicate the value of ONE of the angles.(4)2.4Calculate the tension in the string.(2)2.5The magnitude of force F is equal to the magnitude of the horizontalcomponent of the tension in the string.Give a reason why these two forces are NOT considered to be anaction-reaction pair according to Newton's Third Law.Copyright reservedPlease turn over(1)[11]
8CAPS – Grade 11Physical Sciences/P1DBE/November 2019QUESTION 3 (Start on a new page.)A 4 kg block is pulled up along a frictionless incline by a constant force F acting parallelto the incline, as shown below. The incline makes an angle of 30 with the horizontal.The block moves at CONSTANT VELOCITY.F30 3.1State Newton's First Law of Motion in words.(2)3.2Draw a labelled free-body diagram showing all the forces acting on the block.(3)3.3Calculate the magnitude of:3.3.1The perpendicular component of the weight of the block(3)3.3.2Force F(3)The same block is now pulled up along a rough incline by a constant force of 25 Nacting parallel to the incline, as shown below. The incline makes an angle of 30 withthe horizontal.The acceleration of the block is now 0,2 m·s-2 upwards along the incline.25 N30 3.4Calculate the:3.4.1Magnitude of the kinetic frictional force acting on the block(4)3.4.2Coefficient of kinetic friction between the block and the surface ofthe incline(3)Copyright reservedPlease turn over
DBE/November 2019The force of 25 N acting on the block on the rough incline is now removed, as shownbelow.30 3.5How will EACH of the following quantities change in MAGNITUDE andDIRECTION?3.5.1Weight of the block(2)3.5.2Acceleration of the block(2)3.5.3Kinetic frictional force acting on the block(2)[24]QUESTION 4 (Start on a new page.)A 6 kg block, held at rest on a rough horizontal table, is connected to another block ofmass 3 kg by a light inextensible string passing over a frictionless pulley. The 3 kgblock hangs vertically, as shown in the diagram below.6 kg3 kgWhen the 6 kg block is released, it accelerates to the right and experiences a kineticfrictional force of 24 N. Ignore the effects of air friction.4.1State Newton's Second Law of Motion in words.(2)4.2Draw a labelled free-body diagram showing ALL the forces acting on the6 kg block.(4)4.3Calculate the magnitude of the acceleration of the 3 kg block.(6)4.4Explain the following statement:The acceleration of an object is 0,6 m·s-2.Copyright reserved(2)[14]Please turn over
10CAPS – Grade 11Physical Sciences/P1DBE/November 2019QUESTION 5 (Start on a new page.)The relationship between gravitational acceleration and the ratio of the mass to theMsquare of the radius ( 2 ) of different planets are investigated.RThe graph below is obtained from the data collected.Graph of g versus30g (m·s-2)2520))15g (m ?s105000,51,1,52,02,5113,03,54,04,5-2( 10 kg·m )Mcan be deduced from the graph?5.1What relationship between g and5.2Calculate the gradient of the graph.(3)5.3Which physical constant is represented by the gradient of the graph?(1)5.4The gravitational acceleration on Uranus is 9 m·s-2. Use the graph toMdetermine the 2 value for Uranus.R(2)5.5R2Calculate the mass of Uranus if the radius is 2,54 107 m.Copyright reserved(1)(2)[9]Please turn over
DBE/November 2019QUESTION 6 (Start on a new page.)A light ray is incident on a glass prism. The angle of incidence is 38 , as shown below.The refractive index of glass is 1,5 and that of air is 1.airn38 glass6.1Define the term angle of refraction.(2)6.2Calculate the angle of refraction inside the glass prism.(3)6.3Redraw the glass prism in the ANSWER BOOK. Complete the path of thelight ray inside the prism and label the angle of refraction.(2)A second prism, Q, of unknown material, is now placed next to the glass prism, asshown in the diagram below.airnQ38 glassThe light ray travels from the glass prism and enters prism Q at an angle of incidenceof 36 . The angle of refraction inside prism Q is 41 .6.4Calculate the refractive index of prism Q.(2)6.5How does the speed of light in the glass prism compare to the speed of lightin prism Q? Write only GREATER THAN, SMALLER THAN or REMAINS THESAME.(1)Explain the answer to QUESTION 6.5 by referring to the refractive indices ofthe materials.(2)6.6The critical angle for the glass prism Q boundary is 63,3 . The angle of incidence whenthe light ray travels from the glass prism to prism Q is increased to 65 .6.7Define the term critical angle.(2)6.8What observation will be made? Briefly explain the answer.(3)[17]Copyright reservedPlease turn over
2CAPS – Grade 11Physical Sciences/P1DBE/November 2019QUESTION 7 (Start on a new page.)An experiment is set up to determine the relationship between the DEGREE OFDIFFRACTION and WAVELENGTH of light. Blue light is passed through a single slitand the pattern formed is observed.The experiment is now repeated with green light and then with red light. The distancebetween the light source and the slit remains constant during the investigation.The patterns obtained are shown in the diagram below.BlueGreenRed7.1Define the term wave front.(2)7.2What nature of light is demonstrated by diffraction?(1)7.3For this experiment, write down:7.3.1ONE controlled variable(1)7.3.2The independent variable(1)7.4Fully explain the difference in the patterns observed.(4)7.5The experiment with red light is now repeated using a NARROWER slit.How will the broadness of the central band be affected? Write onlyINCREASES, DECREASES or REMAINS THE SAME. Give a reason for theanswer.Copyright reservedPlease turn over(2)[11]
DBE/November 2019QUESTION 8 (Start on a new page.)Two small identical metal spheres on insulated stands carry charges of 4,2 10-9 Cand -6,8 10-9 C respectively. They are placed at a distance of 0,3 m apart.-6,8 10-9 C 4,2 10-9 C0,3 m8.1State Coulomb's law in words.(2)8.2Calculate the magnitude of the electrostatic force that the one charge exertson the other.(3)The two spheres are allowed to touch and are then returned to their original positions.PQQ0,1 m0,3 m8.3Calculate the new charge Q on EACH sphere.(3)8.4Draw the electric field pattern between the two charged spheres.(2)8.5Calculate the magnitude of the net electric field at point P situated at 0,1 m tothe left of the spheres, as shown in the diagram above.(5)[15]QUESTION 9 (Start on a new page.)A coil with 200 windings and a surface area of 2,8 10-3 m is rotated at constant speedin a constant magnetic field of 2,5 T. An emf of 3,5 V is induced in the coil.9.1Consider the following statement: The magnitude of the induced emf acrossthe ends of a conductor is directly proportional to the rate of change in themagnetic flux linkage with the conductor.Name the law represented by the above statement.9.2Calculate the:9.2.19.2.29.3(1)Change in magnetic flux if the angle of the coil relative to themagnetic field changes from 0 to 90 (3)Time it takes the coil to rotate from 0 to 90 (3)By what factor will the induced emf change if a coil with 100 windings is usedunder the same conditions? Give a reason for the answer.Copyright reservedPlease turn over(2)[9]
14CAPS – Grade 11Physical Sciences/P1DBE/November 2019QUESTION 10 (Start on a new page.)Three resistors, of resistances 3 Ω, 4 Ω and 6 Ω, and a bulb are connected in a circuit,as shown below. Initially all the switches, S1, S2 and S3, are open. The internalresistance of the battery and the resistance of the connecting wires may be ignored.AVS1S2S310.1State Ohm's law in words.(2)Switch S1 is now closed and the voltmeter and ammeter readings are recorded. Thevoltmeter and ammeter readings, when both switch S1 and switch S2 are closed, arethen recorded, as well as the readings when all three switches, S1, S2 and S3, areclosed.The results obtained are shown in the table below.SWITCHESCLOSEDS1S1 and S2S1, S2 and S3VOLTMETERREADING (V)4,867,2AMMETERREADING (A)2,433,610.2Explain the increase in the ammeter reading as more switches are closed.10.3Calculate the:(2)10.3.1Resistance of the bulb(3)10.3.2Potential difference of the battery(4)10.4Define the term power.(2)10.5Calculate the power dissipated in the 6 Ω resistor when ONLY SWITCHES S1and S2 are closed.(4)How will the BRIGHTNESS of the bulb be affected as more switches in thecircuit are closed? Write only INCREASES, DECREASES or REMAINS THESAME.(1)10.610.7Explain the answer to QUESTION 10.6.(2)[20]TOTAL:Copyright reserved150
DBE/November 2019DATA FOR PHYSICAL SCIENCES GRADE 11PAPER 1 (PHYSICS)GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 11VRAESTEL 1 (FISIKA)TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTESNAME/NAAMAcceleration due to gravitySwaartekragversnellingGravitational constantSwaartekragkonstanteRadius of EarthStraal van die AardeCoulomb's constantCoulomb se konstanteSpeed of light in a vacuumSpoed van lig in 'n vakuumCharge on electronLading op elektronElectron massElektronmassaMass of EarthMassa van die AardeSYMBOL/SIMBOOLVALUE/WAARDEg9,8 m·s-2G6,67 x 10-11 N m2 kg-2RE6,38 x 106 mk9,0 x 109 N m2·C-2c3,0 x 108 m·s-1e-1,6 x 10-19 Cme9,11 x 10-31 kgME5,98 x 1024 kgTABLE 2: FORMULAE/TABEL 2: FORMULESMOTION/BEWEGINGvf vi aDtv2f v 2 2aDxiDx v i Dt 21 aDt2æ v vi öDx fDtç è 2 øFORCE/KRAGFnet maGm1m2r2fµ kkNF Copyright reservedw mgfs (max/ maks )µs NPlease turn over
Physical Sciences/P12CAPS – Grade 11WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIGv flT ni sinqi nr sinqrn 1fcvELECTROSTATICS/ELEKTROSTATIKAF kQ1Q2E r2kQr2(k 9,0 x 109 N m2·C-2)E (k 9,0 x 109 N m2·C-2)n FqQeELECTROMAGNETISM/ELEKTROMAGNETISMEe -NDFDtF BA cosqELECTRIC CIRCUITS/ELEKTRIESE STROOMBANEI QDt1 1 1 1 .R r1 r2 r3W VqW VI D tW I RDtR VIR r1 r2 r3 .P WΔtP VI2W P I2RV2ΔtRCopyright reservedP V2RDBE/November 2019
NATIONALSENIOR CERTIFICATE/NASIONALESENIOR SERTIFIKAATGRADE/GRAAD 11PHYSICAL SCIENCES: PHYSICS (P1)FISIESE WETENSKAPPE: FISIKA (V1)NOVEMBER 2019MARKING GUIDELINES/NASIENRIGLYNEMARKS/PUNTE: 150These marking guidelines consist of 13 pages./Hierdie nasienriglyne bestaan uit 13 bladsye.Copyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief
Physical Sciences P1/Fisiese Wetenskappe/V12CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneDBE/November 2019QUESTION 1/VRAAG 11.1B üü(2)1.2C üü(2)1.3A üü(2)1.4B üü(2)1.5B üü(2)1.6C üü(2)1.7D üü(2)1.8B üü(2)1.9A üü(2)1.10D üü(2)[20]Copyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief
DBE/November 2019QUESTION 2/VRAAG 22.12.2Fnet 0/Object in equilibrium/Resultant is zero üüFnet 0/Voorwerp in ewewig/Resultant is nul.(2)w mg (15)(9,8) ü 147 N ü(2)2.3Tw40ºFAccepted Labels/Aanvaarbare ragFApplied force/F/FA/Toegepaste kragTTension/T/SpanningAny angle correctly shown (40 or 50 or 90 )Enige hoek korrek aangedui (40 of 50 of 90 )Mark/PuntüüüüTriangle not closed/Driehoek nie geslote nie: Max./maks. 3 4(4)2.4POSITIVE MARKING FROM QUESTION 2.2.POSITIEWE NASIEN VANAF VRAAG 2.2.OPTION 1/OPSIE 1OPTION 2/OPSIE 2wwT T sin 40 cos 50 147üsin 40 228,69 N ü2.5 147ücos 50 228,69 N ü(2)The two forces act on the same object (the billboard). ü(For the Newton's third law, the forces act on different objects.)Die twee kragte werk op dieselfde voorwerp (die bord) in.(Vir Newton se derde wet moet die kragte op verskillende voorwerpe inwerk.)Copyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief(1)[11]
Physical Sciences P1/Fisiese Wetenskappe/V14DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneQUESTION 3/VRAAG 33.1Marking guidelines/NasienriglyneIf any of the underlined key words/phrases are omitted: minus 1 markIndien enige van die onderstreepte sleutelwoorde/frases uitgelaat is:minus 1 puntA body will remain in its state of rest or motion at constant velocity unless anon-zero resultant/net force acts on it. üü'n Liggaam sal in sy toestand van rus of beweging teen konstante snelheidvolhard tensy 'n nie-nul resulterende/netto krag daarop inwerk.(2)3.2FNwAccepted Labels/Aanvaarbare byskriftew weight/FG/Fggewig/gravitasiekrag/swaartekragN Normal force/FN/Normaalkrag/FNF Force applied/ F /FA/Toegepaste krag Any additional forces/Enige addisionele kragte: Max./maks. 2 3If arrows do NOT touch object/Indien pyle NIE voorwerp raakNIE:Max./maks. 2 3(3)3.3.3.33.3.2Fg mgcos θ ü (4)(9,8)cos 30 ü 33,95 N ü(3)Fnet maü Any one/Enige eenF - Fg// 0F - (4)(9,8)sin 30 0 ü 19,6 N üCopyright reserved/Kopiereg voorbehou(3)Please turn over/Blaai om asseblief
DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne3.43.4.1Fnet maü Any one/Enige eenF - fk - Fg// ma25 - fk - 4(9,8)sin 30º ü 4(0,2) üfk 4,6 N ü(4)POSITIVE MARKING FROM QUESTION 3.3.1 and 3.4.1.POSITIEWE NASIEN VANAF VRAAG 3.3.1 en 3.4.1.fk µkN ü4,6 µk(33,95) üµk 0,135 ü(3)Same in magnitude ü and same in direction üDieselfde grootte en dieselfde rigting(2)3.5.2Increasse in magnitude ü and opposite direction üToeneem in grootte en teenoorgestelde rigting(2)3.5.3Same in magnitude ü and opposite direction üDieselfde grootte en teenoorgestelde rigting3.4.23.53.5.1Copyright reserved/Kopiereg voorbehou(2)[24]Please turn over/Blaai om asseblief
Physical Sciences P1/Fisiese Wetenskappe/V16DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneQUESTION 4/VRAAG 44.1Marking guidelines/NasienriglyneIf any of the underlined key words/phrases are omitted: minus 1 markIndien enige van die onderstreepte sleutelwoorde/frases uitgelaat is:minus 1 puntWhen a resultant/net force act on an object, the object will accelerate in thedirection of the force at an acceleration directly proportional to the forceand inversely proportional to the mass of the object. üüWanneer 'n resulterende/netto krag op 'n voorwerp inwerk, sal die voorwerp indie rigting van die krag versnel teen 'n versnelling direk eweredig aan die kragen omgekeerd eweredig aan die massa van die voorwerp.4.2(2)NfTw(4)Accepted Labels/Aanvaarbare byskriftew weight/Fg/gewig/gravitasiekrag/swaartekragN Normal force/FN/Normaalkrag/FNT Tension/SpanningfFriction/Ff/WrywingüüüüAny additional force/Enige addisionele krag: Max./maks. 3 4If arrows do NOT touch object/Indien pyle NIE voorwerp raakNIE: Max./maks. 3 4(4)4.36 kg block/blok:Fnet ma üT - fk maT - 24 ü 6a üT 6a 24 .(1)3 kg block/blok:Fnet maFg - T ma(3)(9,8) - T ü 3a . (2)Substitute (1) into (2)/Vervang (1) in (2):29,4 - (6a 24) 3a üa 0,6 m·s-2 ü4.4Marking guidelines/Nasienriglyne Formule/Formule: Fnet ma üT – Fk T – 24 üFg - T 3(9,8) – T ü3a OR/OF 6a üEquatingtwoequationsorsubstitute one into the other/Steltwee vergelykingsgelykaanmekaar of vervang die een in dieander. ü Final answer/Finale antwoord:0,6 m·s-2 üThe velocity changes with 0,6 m·s-1 during every second. üüDie snelheid verander met 0,6 m·s-1 gedurende elke sekondeCopyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief(6)(2)
DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneCopyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief[14]
Physical Sciences P1/Fisiese Wetenskappe/V18DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneQUESTION 5/VRAAG 55.1g is directly proportional tog is direk eweredig aan5.2MR2MR2.ü.(1)Any two points from the graph can be used for example:Enige twee punte vanaf die grafiek kan gebruik word byvoorbeeld:9-0 üGradient 1,35 1011 - 0ü 6,67 x 10-11 üOR/OF10 - 0Gradient 1,5 1011 - 0 6,67 x 10-11OR/OF20 - 0Gradient 3 1011 6,67 x 10-11(3)5.3G / Gravitational constant üG / Gravitasie konstante(1)5.41,35 x 1011 (kg m-2) üüRange/Gebied: 1,34 – 1,36 x 1011 (kg m-2)(2)5.5POSITIVE MARKING FROM QUESTION 5.4.POSITIEWE NASIEN VANAF VRAAG 5.4.OPTION 1/OPSIE 1OPTION 2/OPSIE 2MGM 1,35 x 1011g 22RRM6,67 10 11M 1,35 x 1011 ü9 ü(2,54 107 )2(2,54 107 )2M 8,71 1025 kg üM 8,71 1025 kg ü25(8,705 1025 kg)(8,7097 10 kg)Copyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief(2)[9]
DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneQUESTION 6/VRAAG 66.16.2Marking guidelines/NasienriglyneIf any of the underlined key words/phrases are omitted: minus 1 markIndien enige van die onderstreepte sleutelwoorde/frases uitgelaat is:minus 1 puntThe angle between the normal to a surface and the refracted light ray. üüDie hoek tussen die normaal op die oppervlak en die gebreekte ligstraal.(2)nisin θi nr sin θr ü1sin 38º 1,5sin θr üθr 24,23º ü(3)6.338ºθrMarking criteria/Nasienriglyne: Light ray bends towards normal. üLigstraal breek na normal toe. Angle of refraction correctly shown. üBrekingshoek korrek aangetoon.(2)6.4nisin θi nr sin θr1,5sin 36 nr sin 41º ünr 1,34 ü(2)6.5Smaller than üKleiner as(1)6.6For a constant speed of light, c, üthe refractive index is inversely proportional to the speed of light in themedium (v). üTherefore, the higher the refractive index, the lower the speed (v).Vir 'n konstante spoed van lig, c,is die brekingsindeks omgekeerd eweredig aan die spoed van lig in diemedium (v).Dus, hoe groeter die brekingsindeks, hoe kleiner die spoed (v).(2)6.7The angle of incidence when the angle of refraction is 90º. üüDie invalshoek wanneer die brekingshoek gelyk is aan 90º.(2)6.8Total internal reflection occurs übecause the light ray passes from an optical denser to less dense medium üand the angle of incidence is greater than the critical angle. üTotale interne weerkaatsing vind plaasomdat die ligstraal van 'n opties meer dig na minder digte medium beweegen die invalshoek is groter as die grenshoek.Copyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief(3)[17]
Physical Sciences P1/Fisiese Wetenskappe/V110DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneQUESTION 7/VRAAG 77.1Marking guidelines/NasienriglyneIf any of the underlined key words/phrases are omitted: minus 1 markIndien enige van die onderstreepte sleutelwoorde/frases uitgelaat is:minus 1 puntA wave front is an imaginary line joining the points on a wave that are inphase. üü'n Golffront is 'n denkbeeldige lyn wat punte op 'n golf, wat in fase is, verbind.(2)7.2Wave nature üGolfgeaardheid(1)7.3.1Slit width üSpleetwydte(1)7.3.2Colour of light/Wavelength of light üKleur van lig/Golflengte van lig(1)7.4Wavelength increases from blue to red light. ül(Degree of) diffraction α üwFor the same slit width, üdegree of diffraction increases with wavelength. üGolflengte neem toe van blou na rooi lig.l(Mate van) diffraksie αwVir dieselfde spleetwydte,sal mate van diffraksie toeneem met langer golflengte.7.5Increases ü(Degree of) diffraction is inversely proportional to slit width üAfneem(Mate van) diffraksie is omgekeerd eweredig aan spleetwydteCopyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief(4)(2)[11]
DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneQUESTION 8/VRAAG 88.1Marking guidelines/NasienriglyneIf any of the underlined key words/phrases are omitted: minus 1 markIndien enige van die onderstreepte sleutelwoorde/frases uitgelaat is:minus 1 puntThe magnitude of the electrostatic force exerted by two point charges on eachother is directly proportional to the product of the magnitudes of thecharges üand inversely proportional to the square of the distance betweenthem. üDie grootte van die elektrostatiese krag wat deur twee puntladings op mekaaruitgeoefen word, is direk eweredig aan die produk van die grootte van dieladings en omgekeerd eweredig aan die kwadraat van die afstand tussenhulle.8.2F kQ1Q2ür2(9 109 )(4,2 10-6 )(6,8 10-6 )(0,3)2ü 2,86 N ü8.3Q (3)Q1 Q224,2 10-6 (-6,8 10-6 )2 -1,3 10-6 C ü8.4-(2)-ü(2)Criteria for marking/NasienkriteriaCharges correctly indicatedLadings korrek aangeduiShape of the fieldVorm van veldDirection of the fieldRigting van veldNOTE/LET WEL:IF lines don't touch charges or lines cross etc.INDIEN lyne nir doe ladings raak nie of lyne kruis ens.Copyright reserved/Kopiereg voorbehouüüüMax./maks. 2 3Please turn over/Blaai om asseblief(3)
Physical Sciences P1/Fisiese Wetenskappe/V112DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/Nasienriglyne8.5POSITIVE MARKING FROM QUESTION 8.4.POSITIEWE NASIEN VANAF VRAAG 8.4.kQE ür2(9 109 )(1,3 10-6 ) ü0,42-1 73125 N·C rightE (9 109 )(1,3 10-6 )ü0,12 1170000 N·C-1 rightEnet 73 125 1 170 000 ü 1 243 125 N·C-1 ü(5)[15]QUESTION 9/VRAAG 99.1Faraday's law of electromagnetic induction üFaraday se wet van elektromagnetiese induksie(1)9.2.1ΔΦ ΔBAcos θ ü (2,8 x10-3)(2,5)(cos 90º - cos 0º) ü -0,007 Wb ü(3)POSITIVE MARKING FROM QUESTION 9.2.1.POSITIEWE NASIEN VANAF VRAAG 9.2.1.NDfε üDt200(-0,007)3,5 üDtΔt 0,4 s ü(3)9.2.29.3Emf will be halve/two times smaller üEmf is directly proportional to number of windings üEmk sal die helfte wees/twee keer kleinerEmk is direk eweredig aan die aantal windingsCopyright reserved/Kopiereg voorbehou(2)[9]Please turn over/Blaai om asseblief
DBE/November 2019CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneQUESTION 10/VRAAG 1010.1Marking guidelines/NasienriglyneIf any of the underlined key words/phrases are omitted: minus 1 markIndien enige van die onderstreepte sleutelwoorde/frases uitgelaat is:minus 1 puntThe potential difference across a conductor is directly proportional to thecurrent in the conductor at constant temperature. üüDie potensiaalverskil oor die ente van 'n geleier is direk eweredig aan diestroom in die geleier by konstante temperatuur.10.210.310.3.110.3.2(2)More resistors connected in parallel. üTherefor the effective resistance of the circuit decreases. üMeer resistors verbind in parallel.Daarom neem die effektiewe weerstand van die stroombaan af.(2)Any set of values form the table can be used for example:Enige stel waardes vanaf die tabel kan gebruik word byvoorbeeld:VR üI4,8 ü2,4 2Ωü(3)POSITIVE MARKING FROM QUESTION 10.3.1.POSITIEWE NASIEN VANAF VRAAG 10.3.1.OPTION 1/OPSIE 1 OPTION 2/OPSIE 2Switched 1 closed:Switches 1 and 2 closed:Skakelaar 1 gesluit: Skakelaar 1 en 2 gesluit:Rtot 3 2 ü111 5ΩRR R1 1 3 6Rp 2 ΩOPTION 3/OPSIE 3Switches 1, 2 and 3 closedSkakelaar 1, 2 en 3 gesluit1111 Rp R1 R2 R31 1 1 3 6 4Rp 1,33 ΩRtot 2 2 ü 4 ΩRtot 1,33 2 ü 3,33 ΩVemf IRtot ü (3)(4) ü 12 V üVemf IRtot ü (3,6)(3,33) ü 12 V üpVemf IRtot ü (2,4)(5) ü 12 V ü12 Copyright reserved/Kopiereg voorbehouPlease turn over/Blaai om asseblief(4)
Physical Sciences P1/Fisiese Wetenskappe/V114CAPS/KABV – Grade/Graad 11 – Marking Guidelines/NasienriglyneDBE/November 201910.4Power is the rate at which work is done or energy is transferred. üüDrywing is die tempo waarteen arbeid verrig word of energie oorgedra word.10.5POSITIVE MARKING FROM QUESTION 10.3.1 AND 10.3.2.POSITIEWE NASIEN VANAF VRAAG 10.3.1 EN 10.3.2.Vll Vemf - Vseries 12 – 6 ü 6VOPTION 1/OPSIE 1V2P ll üR62 ü6 6WüOPTION 2/OPSIE 2VI R6I 6 1AOPTION 3/OPSIE 3VI R6I 6 1AP VI ü 6(1) ü 6WüP I2R ü 12(6) ü 6Wü(4)10.6Increase/ Neem toe ü10.7(As more resistors are connected in parallel, the effective resistancedecreases and the current increases.)From P I2R, power is directly proportional to I2 üif R (of the bulb) staysconstant.Increase in power increases brightness. ü(1)(Soos meer resistors in parallel verbind word, neem die effektiewe weerstandaf en die stroom neem toe.)Volgens P I2R is die drywing direk eweredig aan I2 indien R (van diegloeilamp) konstant bly.Toename in drywing verhoog helderheid. üTOTAL:Copyright reserved/Kopiereg voorbehou(2)(2)[20]150
Nov 11, 2019 · ANSWER BOOK. 2. This question paper consists of TEN questions. Answer ALL the questions in the ANSWER BOOK. 3. Start EACH question on a NEW page in the ANSWER BOOK. 4. Number the answers correctly according to the numbering system used in this question paper. 5. Leave ONE line
