AP Chemistry Summer Assignment - SharpSchool

Transcription

AP ChemistrySummerAssignmentPHS- Mrs. Riley-LazzariWelcome to AP Chemistry!! You already have a background in chemistry fromyour previous Chemistry class, but AP Chem is very different. Rather thanmemorizing how to do particular types of problems, you must reallyunderstand the chemistry and be able to apply it. AP Chemistry is a difficultcourse because it covers 2 semesters of college chemistry AND lab work.To succeed, you must keep up with the assignments and be willing to spendtime working through the material outside of class. Never tell yourself youdon’t have chemistry homework, each day you should be doing problems orreviewing class material to ensure success come the exam in May. Like all APclasses, AP Chem comes with a summer assignment. I am excited to workwith each one of you and that you have decided to further your chemistrystudies. I hope you learn a lot this year and have fun while you do soJ

The AP chemistry summer assignment is designed torefresh your memory of concepts learned in honors chemistryas well as enhance your non-calculator based mental mathskills. Since you may not have seen this material in a year ormore, it is vitally important that you take this summerassignment seriously. In class, we will focus more on thematerial that is new in order to better prepare you forsuccess on the AP exam in May. There are multiple parts tothe assignment please complete they all as this will startyour year off on the right note and prepared for class.You may email me atcriley@pthsd.net should youhave any questions.Due Date is the First Day ofSchool in September—NoexceptionsThis assignment will becollected in full the first dayof class and there will be atest on the material the firstweek of class. If you did nottake honors chemistry some ofthe material will be new toyou, but it is necessary thatyou study these topics to beprepared for the next school year.Have a wonderful summer J--Mrs. Lazzari

Part 1:Practice multiple choice questions covering chemistry basics.NO calculators allowed.

CHEMICAL FOUNDATIONS, ATOMS, IONS, MOLECULES & STOICHIOMETRY PRACTICE TESTMULTIPLE CHOICE (NO CALCULATOR ALLOWED)1. Which of the following processes requires a chemical change?(A) Separating a sample of saltwater into water and salt(B) Separating a sample of water into hydrogen and oxygen(C) Separating a sample of air into nitrogen, oxygen, and other gases(D) Separating a sample of green ink into a blue component and a yellow component2. Which of the following statements is consistent with Thomson’s and Millikan’s work withcathode rays and electrons?(A) Cathode rays from helium atoms are heavier than cathode rays from hydrogen atoms.(B) Cathode rays are attracted toward a negatively charged electric plate.(C) The mass of an electron is about 2000 times lighter than the mass of a hydrogen atom.(D) The plum pudding model of the atom consists of a uniform sphere of negative charge inwhich the protons are embedded, like raisins in a pudding.3. How many protons, neutrons, and electrons are present in the following ion?56Fe3 Protons Neutrons Electrons(A)263023(B)262629(C)263029(D)2656234. Which of the following calculations is set up correctly to determine the volume (in mL) ofaluminum (density 2.7 g/mL) of a pure sample of Al that contains 2.0 x 1024 atoms?(A)(2.0 1024 )(26.98)(2.7)(6.02 1023 )(C)(2.0 1024 )(2.7)(6.02 1023 )(26.98)(B)(2.0 1024 )(6.02 1023 )(26.98)(2.7)(D)(2.0 1024 )(26.98)(6.02 1023 )(2.7)

5. The mass spectrum of element X is presented in the diagram above. Based on the spectrum,which of the following can be concluded about element X?(A) X is a transition metal, and each peak represents an oxidation state of the metal.(B) X contains five electron sublevels.(C) The atomic mass of X is 90.(D) The atomic mass of X is between 90 and 92.Compound Empirical Formula Mass of Carbon Mass of HydrogenXCH3.0 g0.25 gY?6.0 g1.0 g6. Based on the information shown in the table above, the empirical formula for Compound Y is(A) C2H(B) CH2(C) CH3(D) CH47. The element boron has two naturally occurring isotopes: 10B and 11B.Which of the following represents the most probable data for the relative abundances of thesetwo isotopes?Abundance of boron-10 Abundance of boron-11(A)20%80%(B)40%60%(C)50%50%(D)80%20%

8. What is the empirical formula of an oxide of chromium that is 48 percent oxygen by mass?(A) CrO(B) CrO2(C) CrO3(D) Cr2O3mass of crucible and lid36.0 gmass of crucible, lid, and metal41.0 gmass of crucible, lid, and metal oxide product 43.0 g9. A metallic element is heated in air until the metal reacts completely with oxygen. Given theinformation in the table above, the most probable formula for the metal oxide product is(A) MgO(B) CaO(C) K2O(D) SnO210. According to the information in the table at right,a 1.00 g sample of which of the following containsthe greatest mass of oxygen?(A) Na2O(B) MgO(C) K2OCompoundMolar Mass(grams)Na2O62.0MgO40.3K2O94.2CaO56.1(D) CaO11. The empirical formula of a compound is XF4. This compound contains 1.6 grams of X atomsfor every 3.8 grams of fluorine atoms. The atomic mass of element X is most likely to be(A) 16 amu(B) 32 amu(C) 64 amu(D) 128 amu

12. A sample of a compound that contains only the elements C, H, and N is completely burned inO2 to produce 44.0 g of CO2, 45.0 g of H2O, and some NO2. A possible empirical formula ofthe compound is(A) CH2N(B) CH5N(C) C2H5N(D) C3H3N213. A sample of solid potassium chlorate (KClO3, FW 122.6) was placed in a test tube andheated strongly in the presence of a catalyst until it completely decomposed. The products ofthe decomposition reaction are potassium chloride and oxygen gas (which escaped from thetest tube). If the mass of KClO3 used in the experiment was 12.26 g, how many grams ofoxygen gas were produced in this experiment?(A) 2.4 g(B) 3.2 g(C) 4.8 g(D) 6.4 gPCl5 4 H2O 5 HCl H3PO414. In the reaction represented above, how many molecules of PCl5 are required to reactcompletely with 18 grams of water?(A) 1.5 x 1023(B) 3.0 x 1023(C) 6.0 x 1023(D) 2.4 x 102415. Equal masses of K(s) and Cl2(g) are combined together and allowed to react, producingKCl(s). The reaction proceeds until either one or both of the reactants have been completelyconsumed. At that point, what remains in the reaction vessel?(A) KCl only(B) KCl and K only(C) KCl and Cl2 only(D) KCl, K, and Cl2

16. What is the limiting reactant and the theoretical yield of ammonia when 3.0 g of H2 reacts with7.0 g of N2 ?Limiting Reactant Theoretical Yield of NH3(A)hydrogen8.5 g(B)hydrogen10. g(C)nitrogen8.5 g(D)nitrogen10. g17. In a paper chromatography experiment, asample of a pigment is separated into twocomponents, A and B, as shown in the figureat right. The solvent (water) is polar, andthe surface of the paper is coated with aPigmentSamplematerial that is moderately nonpolar.What can be concluded about A and Bbased on the experimental results?Filter PaperComponent AComponent BWatert 0t 15 min(A) A has a larger molar mass than B does.(B) B has a larger molar mass than A does.(C) A is more polar than B.(D) B is more polar than A.18. The diagram above represents the absorption spectrum for a pure molecular substance. Whichof the following correctly indicates the type of transition observed for the substance in each ofthe regions of the absorption spectrum?Region XRegion YRegion ZMolecular vibrationMolecular rotationElectronic transition(B) Electronic transitionMolecular rotationMolecular vibration(C)Molecular vibration Electronic transition(A)Molecular rotation(D) Electronic transition Molecular vibrationMolecular rotation

NameCHAPTERS 1–3 PRACTICE TESTFREE RESPONSE (CALCULATOR IS ALLOWED)1. Fill in the table with the missing information. Each nuclear symbol should contain the massnumber and the charge.Nuclear Symbol Charge Protons Neutrons Electrons115In3 32P3–3545365681542. For each name, write the correct formula. Indicate if the substance is ionic or covalent.Chemical FormulaNameIonic (I)orCovalent (C)?cobalt(II) carbonatebarium chloratedinitrogen trioxideammonium phosphatesulfur tetrafluoride3. For each formula, write the correct name. Indicate if the substance is ionic or 3O2)2NameIonic (I)orCovalent (C)?

4. A chemist needs to determine the empirical formula of an unknown compound. This compoundcontains the elements C, H, N, and O.A sample of the unknown compound with a mass of 3.8625 g was burned in excess oxygen.The reaction produced 6.8618 g of CO2(g) and 1.7557 g of H2O(g).(a) Determine the mass, in grams, of carbon in the 3.8625 g sample of the compound.(b) Determine the mass, in grams, of hydrogen in the 3.8625 g sample of the compound.(c) When the compound is analyzed for nitrogen content only, the mass percent of nitrogen isfound to be 14.14 percent. Determine the mass, in grams, of nitrogen in the 3.8625 gsample of the compound.(d) Determine the mass, in grams, of oxygen in the 3.8625 g sample of the compound.(e) Determine the empirical formula of the compound.

(f) In another experiment, it was determined that a 8.65-g sample of this compound contained1.75 x 1022 molecules. Calculate the molar mass of this compound.(g) Determine the molecular formula of this compound. Justify your answer.2 C5H12O 15 O2 10 CO2 12 H2O5. Liquid pentanol undergoes complete combustion in the presence of oxygen gas according tothe equation above. In a certain experiment, 7.35 mL of pentanol (density 0.814 g mL-1) isadded to 16.0 L of oxygen gas at 150oC. (density of O2 @ 150oC 0.922 g L-1).(a) Calculate the following quantities.(i) moles of pentanol(ii) moles of oxygen gas(b) Identify the limiting reactant in this experiment. Justify your answer.

(c) Calculate the theoretical yield of carbon dioxide (in grams) that could be produced fromthis experiment.(d) If the mass of carbon dioxide recovered from this experiment is 11.0 g, calculate thepercent yield from this experiment.6. In a laboratory experiment, a student obtained a sample of barium hydroxide hydrate. Thenumber of water molecules in the hydrate formula was unknown. The formula for thiscompound can be written as Ba(OH)2 xH2O, where x indicates the number of moles of waterper mole of Ba(OH)2.A sample of this hydrate was heated strongly in a crucible, in order to drive off the water ofhydration. The anhydrous Ba(OH)2 salt was then treated with excess sodium sulfate solution.This resulted in the formation of a white precipitate, barium sulfate. The precipitate was filteredfrom the solution, dried and weighed. The data table below indicates measurements recordedin this experiment.Mass of clean, dry crucible61.857 gMass of crucible Ba(OH)2 xH2O (before heating) 66.081 gMass of white precipitate, BaSO43.126 g(a) Calculate the mass of the hydrate sample Ba(OH)2 xH2O (before heating).(b) Write a balanced chemical equation for the reaction between barium hydroxide andsodium sulfate.

(c) The mass of the white precipitate was 3.126 g. Calculate the number of moles of thisprecipitate.(d) Calculate the mass of the anhydrous salt, Ba(OH)2.(e) Calculate the mass of water that was lost in the heating process.(f) Calculate the value of x for the sample of Ba(OH)2 xH2O.You are responsible for all of the material covered in this practiceexam. You will be tested on it during the first few days of the schoolyear. After you have completed this packet check your answers at thelink below. Now remember, if you choose to do the opposite ofwhat is being asked and look at the answers first it is only going tohurt your success in AP Chemistry. It is your responsibility tounderstand this material prior to September. You must start the yearoff with a strong foundation of chemistry basics and math skills toensure a successful year in AP Chemistry.https://youtu.be/ZGCUCwO4RGw

Part 2:Independent Study Math Packet

Mathematics Review AP ChemistryAlthough the mathematics on the AP chemistry exam is not difficult, students find it to be challengingbecause most of it requires basic arithmetic skills that you have not used since middle school (or evenelementary school). Students generally have a good sense of how to use a calculator, but lack the skillsof doing math without a calculator. Most math classes stress the use of calculators to solve problems andon the AP chemistry exam at least fifty percent of it is to be done without calculators. You will need topractice the basic math skills that you already know (just haven’t used much in the past) to develop yourthinking to solve the problems that you will encounter.Format of Multiple Choice AP test:v 60 multiple choice questionsv 90 minutes on the sectionv Average time is 90 seconds per questionv NO CALCULATORS ARE TO BE USEDv NO GUESSING PENALTYv Choices go from theo lowest number to the highest numbero they are generally lined up by decimal points, even though this does not make the numberlist “straight”v Allows you to see decimal points and significant figures easier.v Periodic table and formula charts are provided at the beginning of the examv Questions will often be grouped by common given information, but every question will have it’sown four answer choicesSource of these problemsEach problem of the following practice problems are directly related to released AP chemistry examquestions. There will be nothing in this packet that does not directly relate to developing the skills andabilities that students need to be successful on the AP chemistry exam.How to do the mathWhat follows are the notes and the “meat” of this packet. The intent of this packet is to cover the mathnecessary to be successful on the AP Chemistry exam. If it seems to be overly basic in its approach, theunderlining principle in writing this packet is to assume that you (the students) do not remember anything,so we will start at beginning.Thanks to Todd AbronowitzPage 1

Conversion Factors and Dimensional AnalysisThere are two guiding mathematical principles when working with conversion factors.1. When the numerator (the top of a fraction) and the denominator (bottom of the fraction) are thesame, then the fraction equals one.2. When any number is multiplied by one, you do not change the number at all.A conversion factor is a fraction that equals one, since the top and the bottom are the same thing, justexpressed in different units. Examples of conversion factors are:1 dollar 12 inches 365 days 5280 feet 12 eggs 1760 yards 5280 feet,,,,,,.1 year10 dimes1foot1 mile1 dozen 5280 feet 1760 yardsFor the last two, how do you know which one to use? You let the units guide you. You ask yourself aseries of questions as you do the problem.1. What unit has to go on the bottom to cancel?2. What can I change that unit into?3. What numbers will make them equal?Using the units to guide you in the problem is called “dimensional analysis”. This method only works ifyou put your units in the problem and cancel them. Here is the trick you have to think about themcanceling. Don’t just make your teacher happy by canceling units. If you do not get the units to work outand give you what you are asked to find, then you have 100% of getting the problem wrong. If the unitsdo work out, your final unit is what you are asked to find, then you have a 90% chance of getting theproblem right (the other 10% is making dumb mistakes or math errors in your calculations).Say you are 16 years old and you want to know how old you are in minutes. So you start out with 16years.16 years 365 days 24 hours 60 minutes 8 409 600 minutes1 year1 day1 hour1. What unit has to go on thebottom to cancel? Answer: years1. What unit has to go on the bottomto cancel? Answer: days1. What unit has to go on the bottomto cancel? Answer: hours2. What can I change that unit into?Answer: days (you could havepicked months or weeks)2. What can I change that unit into?Answer: hours2. What can I change that unit into?Answer: minutes3. What numbers will make themequal? Answer: 1 year is 365days, so 1 is on the bottom and365 is on the top.3. What numbers will make themequal? Answer: 1 day is 24hours, so 1 is on the bottom and24 is on the top.3. What numbers will make themequal? Answer: 1 day is 60minutes, so 1 is on the bottomand 60 is on the top.Notice that the top and the bottomof the fraction measure the samething, so this conversion factorequals one.Notice that the top and the bottomof the fraction measure the samething, so this conversion factorequals one.Notice that the top and the bottomof the fraction measure the samething, so this conversion factorequals one.Thanks to Todd AbronowitzPage 2

You want to make sure that you cancel as you go. If the units don’t cancel, you made a mistake. Noticealso that all that this problem did was to multiple 16 years by 1, 1 and 1. Anytime that you multiple byone, you do not change the number.A common mistake is that students put the number from the start at the bottom of the first conversion5840 daysfactor, making the problem look like this 16 years . You should never have to reach for a16 yearcalculator to put the numbers in a conversion factor – you should know what the numbers are and wherethe numbers come from!You were asked for your age in minutes but were given years, so you have to convert the units. If thefinal unit is minutes then you have a 90% chance that you got the problem correct.Another method to set up the problem involves “railroad tracks” which is shown below. This method isthe same thing; it is just set up differently. Either setup will get you credit on the AP exam and earn youthe point for showing your work.16 years365 days24 hours1 year1 day60 minutes 8 409 600 minutes1 hourNote on using calculatorsSolve this problem:9.11 x 10 -3136.022 x 10 2355.853.85 -192535.4527965001.60 x 10Students commit two common errors when they reach for their calculator to solve problems like the onesabove. First, the calculator cannot read your mind and will do exactly what you tell it to. If students arenot careful, order of operations will cause you grief. Many students set up these problems correctly onthe free response and then do not earn points because they cannot use their calculator correctly.The second problem is entering scientific notation into your calculators. Take the most common numberin scientific notation used in chemistry, 6.022 x 1023. The “6.022” can be called the coefficient, digit termor the significand while the “x 1023” is called the base or the exponential term. If you use the buttons“10 ” or “ ” to enter scientific notation, you SHOULD (and in some problems MUST) use parenthesisaround the numbers to “glue” the coefficient to the base, if you do not, you may get the wrong answer(depends on the type of problem you are solving). A much better method to enter this information intoyour calculator is to use the “EE” key (graphing calculators), “EXP” key (generally on non-graphingcalculators, but some may have the “EE” key), “E” key (not generally seen) and the “x10” (not generallyseen). By using this key, the calculator automatically “glues” the coefficient with the base.When doing this type of problem, there are two things you want to do use the EE key and use parenthesisaround the top numbers (3.85, 9.11x10-31, 3, 6.022x1023 and 55.85), hit the divide key, and then useparenthesis around the bottom numbers (1.60x10-19, 25, 35.4527 and 96500). This will save you manykeystrokes on the calculator. Reducing the number of keystrokes reduces the number of chances that youhave to make a mistake.Thanks to Todd AbronowitzPage 3

DID YOU KNOWVersion OneThat a horizontal line inmathematicsiscalledavinculum? Its name comes fromthe Latin and it means “bond” or“tied”.It is used in amathematical expression toindicate that the group is to beconsidered “tied” together. Thevinculum can be used to expressdivision. The numerator appearsabove the vinculum and thedenominator beneath it.Version TwoBecause the vinculum means togroup together, we have to usethe parenthesis and the “EE” keyto glue the correct parts togetherso the calculator can do theproblem correctly.Version ThreeVersion FourVersion one is wrong. The student did not use the parenthesis to “glue” the coefficient to the base.Version two is correct. Version three and four are also correct, however, version two only required 60keystrokes, while version three required 70 and version four 91. The fewer keystrokes, the less likely itis that you will make a mistake. The slight difference in the answers for version two/three and versionfour is due to the fact that the numbers in two and three were carried in the memory of the calculator andnot entered by the student.Note on CancelingAs problems are done in this packet, when numbers or units are canceled, not only will the units cancel,but how the units are canceled, will cancel. The ways to show units canceling are “/”, “\”, “—” and “ ”.The “/” was done with the years above, “\” canceled the days and the “—” canceled the hours. This isdone so that it is easier for students to follow what was canceled in the example problems.Cross Canceling of NumbersCross canceling refers to canceling a numerator with a denominator, or a factor that is in each of them. Itis one of the most important skills you need to remember for dealing with the multiple choice problemson the AP chemistry exam. In the first example, the numbers that cancel are side by side, however, on theexam, the numbers may not be side by side. Just remember to cancel numerator with denominator.1Thanks to Todd Abronowitz413 goes into 3,once and the3 goes into 12four times.Page 4

Example:125 125x èx53531è125x 45311the fives cancelExample:7 x 3 x 4 x 3 x 4 x 1 289 143è11112 17 x 3 x 4 x 3 x 4 x 1 1 1289 143 3 2 6122 311MemorizationAlthough this is AP chemistry, you must remember some basic math and arithmetic information. Whatyou have to memorize (and apply) is kept to a minimum; but you MUST know it to be successful on theAP chemistry exam.The first thing to remember is: Divided by ten, decimal point moves to the left one place.Multiple by ten, decimal point moves to the right one place.Divide by powers of ten (100 102, 1000 103, etc) move the decimal point to the left the samenumber of spaces as the power of ten.Multiple by powers of ten (100 102, 1000 103, etc) move the decimal point to the right thesame number of spaces as the power of ten.Another common mathematic problem is division by a fraction. Remember, find the main division barand rewrite as a multiplication problem by multiplying by the reciprocal of the fraction on thedenominator:ac ac a bb bcTo make problems easier, it is generally better to write a mixed fraction as an improper fraction.b(ac) b5(3 x 8) 529Remember a example is 3 cc8883.00A common approach for a problem might be to have you solve the following problem,which can be1.20done “long hand” or you can use the fraction information and division by a fraction to make the problema little easier.3.00 3.00 3.005 3.001 3.00 5 5 2.5061.20 1 166255Thanks to Todd AbronowitzPage 5

The following fractions, their decimal equivalence and their percentages must be memorized.1 0.20 20.0%51 0.125 12.5%81 0.33 33%31 0.50 50%22 0.40 40.0%53 0.375 37.5%82 0.67 67%33 0.60 60.0%55 0.625 62.5%81 0.25 25%44 0.80 80.0%57 0.875 87.5%83 0.75 75%4Once you know these fractions, you can use them to determine other fractions.Example: What is 16 as a decimal?Think of 16 as12of13 ½ of 0.333 0.1667Likewise, you can think of58as 48181218as ½ of ¼, which gives you ½ x ¼ or ½ x 0.25 0.125. You can think of18 0.5 0.125 0.625, so as long as you have the basic list memorized, you should beable to do problems that appear on the test.Example: What is 0.025 as a fraction?First thing is to recognize that the fraction is really based on 0.25, or ¼. But you want 0.025, so that is110.251 114done like this: 0.025 4 x 1010 104 10 401This type of problem often appears when the question is dealing with stoichiometry or titration problemswhere you are given molarities like 0.025 M, 0.0125 M and 0.020 M.If you are given a decimal number like 0.150 M or 0.120 M and it does not fit any of the fractions above,you can also write it as a fraction by moving the decimal to the right until it is behind the last non-zeronumber, and then put it over the appropriate power of 10, which would be 10(number of decimal places moved). Soif you move a decimal 3 places to the right, then it the denominator will become 103, or 1000.1512and 0.120 M becomes. If you have a problem that involves molarities100100like these, work the problem with the fractions; the problem is designed for you to do that.So, 0.150 M would becomeExample is from the 1994 AP test question #55.What volume of 0.150-molar HCl is required to neutralize 25.0 millilters of 0.120-molar Ba(OH)2?Thanks to Todd AbronowitzMolarity molessoluteliterssolutionPage 6

(A) 20.0 mL(B) 30 0 mL(C) 40.0 mL(D) 60.0 mL(E) 80.0 mLFirst step is to write out the balance equation.Ba(OH)2 2 HCl à 2 HOH BaCl2The second step is to place your information so you can do the problem.Ba(OH)2 2 HCl à 2 HOH BaCl225.0 mL0.120 M? mL0.150 MSince the problem said “neutralize” we know that the moles of acid and the moles of base arestoichiometrically equal.1512So, the first thing to do is to rewrite the molarities as fractions,and.100100Next, find the moles of Ba(OH)2, moles molarity x volume.æ 12 ö molesæ 12 öæ 251ö 12moles molarity volume ç 25.0 milliliters ç 3 millimoles ç è 100 ø literè 100 øè 1 ø 44Next find the number of moles HCl.3.0 millimoles Ba(OH)2 2 moles HCl1 mole Ba(OH) 6 millimoles HCl2Last step is to find the volume of HCl used. Volume equalsvolume moles6 millimoles HCl molarity æ 15 öæ moles ö ç çè 100 øè liters ømoles.molarityNotice that I only cancelledthe “liters” part of themilliliters.This wouldleave a “milli” and that willbe multiplied by the molesto get millimoles. You can“track” the “milli” throughthe problem.202æ 100 öæ liters ö 6 millimoles HCl ç 40.0 milliliters çè 15 øè moles ø51A common type of problem will require you to use scientific notation and to use the following exponentlaws (which need to be memorized):Thanks to Todd AbronowitzPage 7

am an am nam an am - na0 1a-n (a )mn am n( ab )m a mb m1( a ¹ 0)anExample: A problem gives you the Keq value of 2.0 x 107 and would like the Keq value for the reversereaction, which is the reciprocal of the given Keq value.Answer:11 1001 100-7 0.5 10-7 5 10-8772.0 102.0 102Another way to do this problem is to rewrite 1 as 10 x 10-1. Doing this, you will have:110 10-1 10 10-1-7 5 10-8772.0 102.0 102.0This trick is very helpful when you have to do division. It allows you to get a whole number directly fromthe problem and not have to try to move the decimal point in scientific notation (like the first methoddoes).The last exponent rule is commonly used on the AP exam with units (both on the formula charts and in1problems). The exponent law that says a - n n will often show up on the test with units like sec-1 (whicha1111means sec -1 ) or mol-1 () or K-1 ( ). When you are doing kinetic problems, you will see 1Kmolsec sec211litersliters 2 1x units like, M-2 ( M - 2 2 ).Mmol 2mol 2mol 2liter 2You will also need to remember your “perfect squares” from 1 to 12.12 122 432 942 1652 2562 3672 4982 6492 81102 100112 121122 144Scientific NotationIn science, the numbers are characteristically very large (a mole is 602 214 179 000 000 000 000 000) orvery small (the charge carried by an electron is 0.000 000 000 000 000 000 160 217 653 coulombs).Scientific notation is used to conveniently write the numbers using powers of ten. So 1,650,000 can bewritten (with four significant figures) as 1.650 x 106 (which generally will be written as 1.650 x 106 itmakes it easier for people to see the exponent). This can be thought of as 1.650 x 10 x 10 x 10 x 10 x 10x 10 (six sets of 10, since the exponent was 6).Notice that1.650 x 10 x 10 x 10 x 10 x 10 x 10 16.50 x 10 x 10 x 10 x 10 x 10Thanks to Todd AbronowitzA note about commas and numbers:Most textbooks will not use commas toseparate numbers into groups of three.They will add a space instead, so1,650,000 Pagewill be8written as 1 650 000– this is because in other countries, acomma in a number is read as adecimal point and you can’t have two

165.0 x 10 x 10 x 10 x 10 1650. x 10 x 10 x 10 16500. x 10 x 10 165000. x 10 1,650,000So by multiplying by 10, we are moving the decimal place over to the right that many times and get anumber bigger than one.Likewise, if we have a number that is smaller than one, we should divide by powers of 10 and move thedecimal point to the left. So 0.000321 can be thought of as:3.213.21 3.21 x 10 0 4 3.21 x 10 0- 4 3.21 x 10 - 410 x 10 x 10 x 10 1010 4Remember that 100 is 1 and anything multiplied by one is still itself.Students have a problem sometimes in remembering if the exponent is positive or negative. The easiestway to remember this is to ask yourself “is the original number less than one?” The answer to this questionwill determine if your exponent is positive or negative.Is the original number less than one?Exponent will beExamplesYesNegative0.0025 2.5 x 10-3NoPositive (or zero)320500 3.205 x 105Powers and RootsJust as operations of addition and subtraction and the operations of multiplication and division are relatedto each other (in math terms they are inverse operations of each other), so are exponents and roots. When2is called the9 is written, the 2 is called the “index”, the 9 is called the “base” or “radicand” and the“radical” or “root”. When the index is “2”, we often call it “square root”.Fractional exponents can be used to represent taking the “root” of a number, thus29 can also be written1as 9½, likewise 8 3 is an

The AP chemistry summer assignment is designed to refresh your memory of concepts learned in honors chemistry as well as enhance your non-calculator based mental math . CHAPTERS 1-3 PRACTICE TEST Name FREE RESPONSE (CALCULATOR IS ALLOWED) 1. Fill in the table with the missing information. Each nuclear symbol should contain the mass