8 MTXESK065802 U1M01 - San Juan Unified School District

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Solutions Key

Cover Image Credits: Death Valley Felix Stensson/AlamyCopyright by Houghton Mifflin Harcourt Publishing CompanyAll rights reserved. No part of this work may be reproduced or transmitted in any form or by any means,electronic or mechanical, including photocopying or recording, or by any information storage and retrievalsystem, without the prior written permission of the copyright owner unless such copying is expresslypermitted by federal copyright law. Requests for permission to make copies of any part of the work shouldbe addressed to Houghton Mifflin Harcourt Publishing Company, Attn: Contracts, Copyrights, and Licensing,9400 Southpark Center Loop, Orlando, Florida 32819-8647.Printed in the U.S.A.ISBN978-0-544-20724-01 2 3 4 5 6 7 8 9 10 XXXX 22 21 20 19 18 17 16 15 14 134500000000BCDEFGIf you have received these materials as examination copies free of charge, Houghton Mifflin HarcourtPublishing Company retains title to the materials and they may not be resold. Resale of examinationcopies is strictly prohibited.Possession of this publication in print format does not entitle users to convert this publication, or anyportion of it, into electronic format.

Table of ContentsUNIT 1 Real Numbers, Exponents,and Scientific NotationUNIT 3 Solving Equations andSystems of EquationsModule 1Lesson 1.1 . . . . . . . . . . . . . . . . . . . . . . . . . 1Lesson 1.2 . . . . . . . . . . . . . . . . . . . . . . . . . 4Lesson 1.3 . . . . . . . . . . . . . . . . . . . . . . . . . 5Module 7Lesson 7.1. . . . . . . . . . . . . . . . . . . . . . . . .Lesson 7.2. . . . . . . . . . . . . . . . . . . . . . . . .Lesson 7.3. . . . . . . . . . . . . . . . . . . . . . . . .Lesson 7.4. . . . . . . . . . . . . . . . . . . . . . . . .44464851Module 8Lesson 8.1Lesson 8.2Lesson 8.3Lesson 8.4Lesson 8.55558636670Module 2Lesson 2.1Lesson 2.2Lesson 2.3Lesson 2.4. 8. . . . . . . . . . . . . . . . . . . . . . . . .11. . . . . . . . . . . . . . . . . . . . . . . . 12. . . . . . . . . . . . . . . . . . . . . . . . 14UNIT 2 Proportional andNonproportional Relationshipsand FunctionsUNIT 4 Transformational GeometryModule 3Lesson 3.1 . . . . . . . . . . . . . . . . . . . . . . . . 19Lesson 3.2 . . . . . . . . . . . . . . . . . . . . . . . . 20Lesson 3.3 . . . . . . . . . . . . . . . . . . . . . . . . 22Module 4Lesson 4.1Lesson 4.2Lesson 4.3Lesson 4.4.Module 9Lesson 9.1Lesson 9.2Lesson 9.3Lesson 9.4Lesson 9.524262729.Copyright by Houghton Mifflin Harcourt.All rights reserved.7476787980Module 10Lesson 10.1 . . . . . . . . . . . . . . . . . . . . . . . 83Lesson 10.2 . . . . . . . . . . . . . . . . . . . . . . . 84Lesson 10.3 . . . . . . . . . . . . . . . . . . . . . . . 85Module 5Lesson 5.1 . . . . . . . . . . . . . . . . . . . . . . . . 32Lesson 5.2 . . . . . . . . . . . . . . . . . . . . . . . . 33Lesson 5.3 . . . . . . . . . . . . . . . . . . . . . . . . 35Module 6Lesson 6.1Lesson 6.2Lesson 6.3Lesson 6.4.38394142iii

Table of ContentsUNIT 5 Measurement GeometryUNIT 6 StatisticsModule 11Lesson 11.1. . . . . . . . . . . . . . . . . . . . . . . . 88Lesson 11.2. . . . . . . . . . . . . . . . . . . . . . . . 89Lesson 11.3. . . . . . . . . . . . . . . . . . . . . . . . 91Module 14Lesson 14.1 . . . . . . . . . . . . . . . . . . . . . . 107Lesson 14.2 . . . . . . . . . . . . . . . . . . . . . . 108Module 15Lesson 15.1 . . . . . . . . . . . . . . . . . . . . . . .110Lesson 15.2 . . . . . . . . . . . . . . . . . . . . . . 112Module 12Lesson 12.1 . . . . . . . . . . . . . . . . . . . . . . . 93Lesson 12.2 . . . . . . . . . . . . . . . . . . . . . . . 95Lesson 12.3 . . . . . . . . . . . . . . . . . . . . . . . 97Module 13Lesson 13.1 . . . . . . . . . . . . . . . . . . . . . . 100Lesson 13.2 . . . . . . . . . . . . . . . . . . . . . . 102Lesson 13.3 . . . . . . . . . . . . . . . . . . . . . . 104Copyright by Houghton Mifflin Harcourt.All rights reserved.iv

Solutions KeyUNIT1Real Numbers, Exponents, and Scientific NotationMODULE 1 Real Numbers520. 56Are You Ready?1. 7 7 4955 62. 21 21 441303. ( –3) ( –3) 93566164 4 4.5 5 25LESSON 1.15. ( 2.7) ( 2.7) 7.29( ) ( )1 -1 16. -44167. ( –5.7) (–5.7 ) 32.49Your Turn0.451. 11 5.005 2 2 78. 15 5 5 5-4460-555Because the number 5 repeats during the divisionprocess, the answer is a repeating decimal: 0.45.49 17 24 or 19.6 5 252529. 9 9 9 8175410. 2 2 2 2 2 16( 31 )21 1 1 3 3 912. ( –7)2 ( –7) (–7 ) 4911.0.1252. 8 1.000-8201640-4000.125313. 4 4 4 4 6414. ( –1)5 ( –1) (–1 ) ( –1 ) (–1 ) (–1) –115. ( 4.5)2 (4.5 ) ( 4.5) 20.25516. 10 10 10 10 10 10 100,000117. 333 1 73. 23 32.33 7.0-61091Because the number 1 repeats during the divisionprocess, the answer is a repeating decimal: 2.3.139 13 3103518. 1851 84. Write the decimal 0.12 as a fraction.120.12 100Simplify using the same numerator anddenominator.12 4 3100 4 2558 8 8138319. 2732 71473 7177Copyright by Houghton Mifflin Harcourt.All rights reserved.5 61

5.x 0.57( 100 )x 100( 0.57 )100x 57.57Becausex 0.57, subtract x from one side and0.57 from the other.100x 57.57-x -0.5799x 575799x 99991957 , orx 993382.90.89 8.0-728Because the number 8 repeats during the divisionprocess, the answer is a repeating decimal: 0.8.15 , so3 can also be written as3. 3443.754 15.00-12302820-2003.7574.100.710 7.0-7000.7193 can also be written as5. 2882.3758 19.000-16302460-56404002.37556.60.836 5.00-4820-1820Because the number 20 repeats during the divisionprocess, the answer is a repeating decimal: 0.836. Write the decimal 1.4 as a fraction.141.4 10Simplify using the same numerator anddenominator.14 2 7510 27 , or 12557.x2 196 X2 196X 196X 14The solutions are 14 and -14.298. x 2569 X2 2569x 2563x 163.3 and -The solutions are161639.512 x33 512 x33 512 x 8 xThe solution is 8.6410. x3 3433 364 x 33434x 74.The solution is7 7. Write the decimal 0.675 as a fraction.6750.675 1000Simplify using the same numerator anddenominator.675 25 271000 25 40Guided Practice21.50.45 2.0-2000.4Copyright by Houghton Mifflin Harcourt.All rights reserved.8. The decimal 5.6 is the can be written as3.6 , or 55 5102

9. Write the decimal 0.44 as a fraction.440.44 100Simplify using the same numerator anddenominator.44 4 11100 4 2510. 10x 4.4-x - 0.49x 44x 911. 100x 26.26-x - 0.2699x 2626x 9912. 1000x 325.325-x- 0.325999x 325325x 99914 , so4 can also be written as22. 2552.85 14.0-1040-400The distance is 2.8 km.13. x2 17x 17 4.122514. x 289525 x 1728924. Write the decimal 0.8 as a fraction.80.8 10Simplify using the same numerator anddenominator.8 2 410 2 54 second.A heartbeat takes5296 , so2 can also be written as23. 983398.63 296.00-2726-24201820Because the number 20 repeats during the divisionprocess, the answer is a repeating decimal: 98.6innings. 15. x 2163x 216 6316. 5 2.225. Separate the decimal from 26.2 so that:20.2 10Simplify using the same numerator anddenominator.2 2 110 2 51 mi.Therefore, 26.2 mi 26517. 3 1.718. 10 3.2a,19. Rational numbers can be written in the formbwhere a and b are integers and b 0. Irrationalnumbers cannot be written in this form.Independent Practice26. Separatethe repeating digit and let x 0.1x 0.1( 100 )x 100( 0.1 )100x 11.1-x-0.199x 1111x 991x 91.Therefore, 72.1 729720.160.437516 7.0000-646048120-112808000.4375 in.121.60.166 1.00-640-3640Because the number 40 repeats during the divisionprocess, the answer is a repeating decimal: 0.16.Copyright by Houghton Mifflin Harcourt.All rights reserved.27. Write the decimal 0.505 as a fraction.5050.505 1000Simplify using the same numerator anddenominator.505 5 1011000 5 200101 cent.A metal penny is worth2003

28. a. You can set up the equation x2 400 to find thelength of a side.x2 400 x2 400x 20The solutions are x 20; the equation has 2solutions.b. The solution x 20 makes sense, but thesolution x -20 doesn’t make sense, because apainting can’t have a side length of -20 inches.c. The length of the wood trim needed is4 20 80 inches.Because the expressions yield the same answer, aa . Therefore, you canyou can see thatb bmake a conjecture about the multiplicationrule forsquare roots that a · b a · b . 38. The value of a is 225, because the solutions arex 15, and 15 - (-15 ) 30.LESSON 1.2Your Turn2 is a rational number because it can be1. 12338 . It is a real numberrepresented as the ratio3because all rational numbers are real numbers.2x 1429. x2 14x 3.730.32x 14431.3. False. Every integer is a rational number, but notevery rational number is an integer. For example,5 are not3 and -rational numbers such as52integers. x2 144x 122x 2932. x2 294. False. Real numbers are either rational numbers orirrational numbers. Integers are rational numbers, sono integers are irrational numbers.x 5.433. His estimate is low because 15 is much closer to 16than it is to 9. So, a better estimate would be higher,such as 3.8 or 3.9.5. The set of real numbers best describes the situation.The amount can be any number greater than 0.6. The set of rational numbers best describes thesituation. A person’s weight can be a decimal suchas 83.5 pounds.34. Sample answer: A good estimate is x 4.5,because 43 64 and 53 125. Since95 is about3half way between 64 and 125, 95 is probablycloser to 4.5 than to 4 or 5.4 r335.V 3436 r 3344436 r3 3 3327 r 333 27 r 33 rThe radius of the sphere is 3 feet.Guided Practice7 is a rational number because it is the ratio of two1.8integers: 7 and 8. It is a real number because allrational numbers are real numbers.2. 36 is a whole number because it is equal to 6,which is a positive number with no fractional ordecimal part. Every whole number is also an integer,a rational number, and a real number.3. 24 is an irrational number because 24 is a wholenumber that is not a perfect square. It is a realnumber because all irrational numbers are realnumbers.Focus on Higher Order Thinking36. Yes; the cube root of a negative number is alwaysnegative, because a negative number cubed isalways negative, and a nonnegative number cubedis always nonnegative. 44 2 , and2 37.5525 25 1616 4 , and4 8199 81 2. The length of the side is 10 yd. 10 is an irrationalnumber because 10 is a whole number that is not aperfect square. It is a real number because allirrational numbers are real numbers.x 13313 33 x 1331x 114. 0.75 is a rational number because it is a terminatingdecimal. It is a real number because all rationalnumbers are real numbers.5. 0 is a whole number because it is a number withno fractional or decimal part. Every whole numberis also an integer, a rational number, and a realnumber. 3636 6 , and6 7749 49Copyright by Houghton Mifflin Harcourt.All rights reserved.6. - 100 is an integer because it is equal to -10,which is a number with no fractional or decimal part.Every integer is also a rational number and a realnumber.4

7. 5.45 is a rational number because it is a repeatingdecimal. It is a real number because all rationalnumbers are real numbers.18 is an integer because it is equal to -3, which is8. -6a number with no fractional or decimal part. Everyinteger is also a rational number and a real number.21. The set of integers best describes the situation. Thescores are counting numbers, their opposites, and 0.22. Nathaniel is correct. A rational number is a number1 is a fraction.that can be written as a fraction, and11π23. A whole number. The diameter isπ mi, or 1 mi.9. True. Whole numbers are a subset of the set ofrational numbers and can be written as a fractionwith a denominator of 1.24. It can be a rational number that is not an integer, oran irrational number.25. The total number of gallons of milk is either a wholenumber or a mixed number in which the fractional1 . Therefore, the number is a rational number.part is210. True. Whole numbers are rational numbers.11. The set of integers best describes the situation.The change can be a whole dollar amount andcan be positive, negative, or 0.Focus on Higher Order Thinking26. The set of negative numbers also includesnon-integer rational numbers and irrational numbers.12. The set of rational numbers best describes the1 inch.situation. The ruler is marked every1613. Sample answer: Describe one set as being a subsetof another, or show their relationships in a Venndiagram.27. Sample answer: If the calculator shows a decimalthat terminates in fewer digits than what thecalculator screen allows, then you can tell that thenumber is rational. If not, you cannot tell from thecalculator display whether the number terminatesbecause you see a limited number of digits.It may be a repeating decimal (rational) or anon-terminating non-repeating decimal (irrational).1 1. Since28. It is a whole number. 3 · 0.3 3 ·33 · 0.3 is equal to 0.9, then 0.9 is equal to 1, whichis a whole number.Independent Practice14. - 9 is an integer because it is equal to -3. Everyinteger is also a rational number and a real number.15. 257 is a whole number because it is a positivenumber with no fractional or decimal part. Everywhole number is also an integer, a rational number,and a real number.16. 50 is an irrational number because 50 is awhole number that is not a perfect square. It is areal number because all irrational numbers are realnumbers.1 is a rational number because it can be17. 8217 . It is a real numberrepresented as the ratio2because all rational numbers are real numbers.29. Sample answer: In decimal form, irrational numbersnever terminate and never repeat. Therefore, nomatter how many decimal places you include, thenumber will never be precisely represented. Therewill always be more digits.LESSON 1.3Your Turn18. 16.6 is a rational number because it is a terminatingdecimal. It is a real number because all rationalnumbers are real numbers.19. 16 is a whole number because it is equal to 4,which is a positive number with no fractional ordecimal part. Every whole number is also an integer,a rational number, and a real number.16.6Integers182Irrational Numbers 505. 5 is between 2 and 3, but is closer to 2. So5 2.5. 3 is between 1 and 2, so 3 1.5. 3 , 5 , 2.5Whole Numbers 9 1612 is between 3 and 4, so 12 3.5.4. 12 6 3.5 6 9.5 6 is between 2 and 3, so 6 2.5.12 6 12 12.5 14.5Since 9.5 14.5, 12 6 12 6 .Real NumbersRational Numbers3. 2 is between 1 and 2, so 2 1.5. 2 4 1.5 4 5.5 4 22 4 2 2 4Since 5.5 4, 2 4 2 4 .257 3020. The set of real numbers best describes the situation.The height can be any number greater than 0.Copyright by Houghton Mifflin Harcourt.All rights reserved.50.511.5 522.533.54

6. An approximate value of π is 3.14. So,π2 9.8956. 75 is between 8 and 9, so 75 8.5.2 75 , π , 10 7588.5 3π2909.5 10 10.5 11 11.5 121. 3 is between 1 and 2, so 3 1.5. 3 2 1.5 2 3.5 3 3 1.5 3 4.5Since 3.5 4.5, 3 2 3 3.8 is between 2 and 3 but very close to 3. Use 2.8.2. 8 17 2.8 17 19.8 11 is between 3 and 4, so 11 3.5. 11 15 3.5 15 18.5Since 19.8 18.5, 8 17 11 15.7 2.259 , -3.75,8, 342216. a. A 3.5 12.25 m2b. C π · 4 4π m4π 4 · 3.14 12.6 m2c. The circle would give her more space to plantbecause it has a greater area.17. a. 60 is between 7.7 and 7.8, so 60 7.75.58 7.2587.3 7.333 7.60757.75 7.25 7.33 7.60 29.93 7.482544The average is 7.4825 km.is between1 and 2, so 1.5.12 - 2 12 - 1.5 10.5 8 is between 2 and 3, so 8 2.514 - 8 14 - 2.5 11.5Since 10.5 11.5, 12 - 2 14 - 8 .7 is between 2 and 3, so 7 2.5.7. 7 2 2.5 2 4.5 10 is between 3 and 4, so 10 3.5. 10 - 1 3.5 - 1 2.5Since 4.5 2.5, 7 2 10 - 1.b. 56 7.4833, which is slightly greater than, butvery close to, Winnie’s estimate.17 is between 4 and 5, but very close to 4. Use 4.1.8. 17 3 10 - 2.5 7.5 11 is between 3 and 4, so 11 3.5.3 11 3 3.5 6.5Since 7.5 6.5, 17 3 3 11 .Copyright by Houghton Mifflin Harcourt.All rights reserved.645917 is between 4 and 5, but very close to 4. Use 4.1.5. 17 - 3 4.1 - 3 1.1 5 is between 2 and 3, but very close to 2. Use 2.2.-2 5 -2 2.2 0.2Since 1.1 0.2, 17 - 3 -2 5 .4 8 8 is between 2 and 3, so 8 2.5 and 1.75.2 8, 2, 72is between 3.1 and 3.2, so 10 3.15. π 3.14.13. 10π, 10 , 3.5220 is between 14 and 15, so 220 14.5.14. 100 10-10, 100 , 11.5, 22015. 8 is between 2 and 3, so 8 2.5.9 34. 9 3 3 3 6 3 is between 1 and 2, so 3 1.5.9 3 9 1.5 10.5Since 6 10.5, 9 3 9 3 .6.312. 7 is between 2 and 3, so 7 2.5. 22Independent Practice6 is between 2 and 3, so 6 2.5.3. 6 5 2.5 5 7.5 5 is also between 2 and 3, but will be a bit lessthan 2.5.Use 2.3.6 5 6 2.3 8.3Since 7.5 8.3, 6 5 6 5 . 212π10. 17 is between 4and 5 but very close to 4, so 17 4.1, and 17 - 2 2.1.π 2.57.π 1.57, and 1 π 3.14, so2212 2.45π km, 2.5 km,12 km, 17 - 2 km1 5211. Sample answer: Convert each number to a decimalequivalent, using estimation to find equivalents forirrational numbers. Graph each number on a numberline. Read the numbers from left to right to order thenumbers from least to greatest. Read the numbersfrom right to left to order the numbers from greatestto least.10 3.1 3.57.3; 332 10 is between 3 and 4, but is very close to 3.So 10 3.3.10 mi, 1 mi, 3.45 mi,10 mi323Guided Practice9. 3 is between 1.7 and 1.8, so 3 1.75.π 3.14,so 2π 6.281.5, 3 , 2π18. Sample answer: 3.7.19. Sample answer: 31 .20.6115 is between 10.7 and 10.8, so 115 10.75.115 10.4511Neither student is correct. The answer should be:115 , 10.5624, 115 .11

7 2.65 and 8 2.83, е is between21. a. Since 7 and 8 . 9 3 and 10 3.16, π is betweenb. Since 9 and 10 .5.Focus on Higher Order Thinking22 3.142922. a.73.143.1403.1413.142x 76.103.1431-107. Each side measures 200 ft.14.12 198.81; 14.22 201.64 so,200 is between 14.1 and 14.2. 200 14.1Each side is approximately 14.1 feet long. 3.1429. It is closer to π on the number line.7x 3.1416c.113x 113 · 3.1416x 355.0008355121is a whole number because8. 121121 11, and 11 is a positive number with121 11121no fractional or decimal part. Every whole number isalso an integer, a rational number, and a realnumber.23. 2; Rational numbers can have the same location,and irrational numbers can have the same location,but they cannot share a location.24. She did not consider that 12.6 12.66 .MODULE 1π is an irrational number because π is an irrational9.2number and dividing π by 2 gives another irrationalnumber. It is a real number because all irrationalnumbers are real numbers.Ready to Go On?0.351. 20 7.00-60100-10000.3510. True; Integers can be written as the quotient of twointegers.11. 8 is between 2 and 3, so 8 2.5. 8 3 2.5 3 5.5 3 is between 1 and 2, so 3 1.5.8 3 8 1.5 9.5Since 5.5 9.5, 8 3 8 3 .x 1.27( 100 )x ( 100 )1.27100x 127.27Becausex 1.27, subtract x from one sideand 1.27 fromthe other.100x 127.27-x-1.2799x 12612699x 999914 115 is between 2 and 3, so 5 2.5.12. 5 11 2.5 11 13.5 11 is between 3 and 4, so 11 3.5.5 11 5 3.5 8.5Since 13.5 8.5, 5 11 5 11 .213. π 9.87, 9.8 9.88, and 99 9.95.Therefore, the orderfrom least to greatestshould be π2, 9.8, 99 .157 3. 1881.8758 15.000-870-64605640-4001.875Copyright by Houghton Mifflin Harcourt.All rights reserved.11 1 ; -1 - 10010100101 and22b.2.x3 3433 33 x 343227π4. 81 9; - 81 -99 and -914.1 1 0.20 5251 0.250.2 0.22 11 , 0.2,2544 15. Sample answer: Real numbers, such as the rational1 , can describe amounts used in cooking.number47

[ ( 6 - 1 )2 ]210.( 3 2 )3[ ( 5 )2 ]2 ( 5 )3( 25 )2 ( 5 )3625 125 52 3-511. (2 ) - (10 - 6 )3 · 42 )33-5( 2 -4 ·4 26 - 43 · 4-5() 26 - 43 -56-2 2 -41 64 -1615 6316MODULE 2 Exponents and Scientific NotationAre You Ready?1. 10210 1010032. 1010 10 10100053. 1010 10 10 10 10100,00074. 1010 10 10 10 10 10 1010,000,0005. 45.3 1045.3 100045,3003Guided Practice6. 7.08 107.08 1000.07081. As the exponent decreases by 1, the value of thepower is divided by 8.80 1 118 827. 0.00235 100.00235 1,000,0002,35062. As the exponent decreases by 1, the value of thepower is divided by 6.60 1-116 616-2 368. 3,600 103,600 1,0000.3649. 0.5 100.5 1005023. Any number raised to the power 0 equals 1.2560 110. 67.7 1067.7 100,0000.00067754. As the exponent increases by 1, the value of thepower is multiplied by 10.100 1101 10102 10011. 0.0057 100.0057 1,0005745. As the exponent increases by 1, the value of thepower is multiplied by 5.50 151 552 2553 12554 62512. 195 10195 1,000,0000.0001956LESSON 2.1Your Turn6. As the exponent decreases by 1, the value of thepower is divided by 2.20 1-112 212-2 412-3 8-42 116-52 1327. ( 2 · 11 )2 222 4842 )32·3(8. 2 2 26 643-4-13-4-19. 5 · 5 · 5 5-2 51 521 25Copyright by Houghton Mifflin Harcourt.All rights reserved.8

90-109 0-1018. 6 · 6 · 6 67. As the exponent decreases by 1, the value of thepower is divided by 4.40 1-114 4-24 11614-3 6414-4 25614-5 1024 6-11 611 62710 · 10 102 7-519.510 104 10,000220. (10 - 6 )3 · 4 ( 10 2)232 4 · 4 122 43 2 122 45 122 1,024 144 1,1688. Any number raised to the power 0 equals 1.890 19. As the exponent decreases by 1, the value of thepower is divided by 11.110 1-1111 11111-2 121111-3 1331( 12 - 5 )721.[ (3 4)2 ]277 (72)277 72·277 7410. 4 · 4 · 4 41 · 41 · 41 41 1 1 4311. 77-4 73 343···2· (21 · 21) · (21 · 21 · 21) (21 1) · (21 1 1) 22 · 23 25(22)(22)22. Sample answer: When multiplying powers with thesame base, you add the exponents. When dividingpowers with the same base, you subtract theexponents. When raising a product to a power, youraise each factor to that power. When raising apower to a power, you multiply the exponents.7612.656·6·6·6·6·6·6 6·6·6·6·61·61 · 61 · 61 · 61 · 61 · 616 61 · 61 · 61 · 61 · 611 1 1 1 1 1 16 61 1 1 1 176 6523. 5-7 · 512 · 5-2 5-7 12-2 53 125()7 -2() 812 · 87 · -224. 8 · 812 812 · 8-14 67-5 812-14 62 8-21 821 6481213.89 812-925. 5 · (3 · 5 )2 5 · 152 83 5 · 2251014. 5 · 5 · 5 510 · 51 · 51 510 1 1 5122926.5915. 7 · 7 78 5 7132·482 4 616. ( 6 ) 685 9 9-31 931 7293317. ( 8 · 12)3 8 · 12Copyright by Houghton Mifflin Harcourt.All rights reserved. 1,1252-59

2·5(62)527. 6 8866106 8635. 4-5 610-8· (4 · 9)5 · 9-3 4-5 · (45 · 95 ) · 9-3 Power of aProductProperty-5553 (4 · 4 ) · (9 · 9 ) AssociativeProperty 62 361110 1110-(3 5)28.113 · 115 1110-8 112 1212 307-52·3 20 27-529. ( 2 ) 2 2 · 2 2 26 20 22 69-2· ( 7 - 4)2 (7 4 )2 3-2 (3 )2 112 3-2 2 112 1 · 92Zero ExponentProperty 92Identity Property ofMultiplication 81Definition of anexponentIndependent Practice 30 11237. The exponents cannot be added because the basesare not the same. 1 121 122538. To express 3 as a product of powers, the basesshould be 3 and the powers should add up to 5;Sample answer: 35 · 30; 34 · 31; 33 · 324431. 10 · [ ( 8 2)2 ]-3 10 · [ ( 10 )2 ]-3 104 · 102 · (-3)7439. 22 22 ;722224 227-4 104 · 10-6 104-6 10-21 1021 100545( )7 ( 2 5 )4 7( 7)732.7(8 - 1)7 75 4-7 223 10,648The distance from Earth to Neptune is the greaterdistance. It is about 10,648 times greater than thedistance from Earth to the moon.40. The student is not correct because()1 1 , which is less83 · 8-5 83 -5 8-2 82 64than 1.2 n-641. (b ) b2n -6-62n 22n -3(b2)-3 b-6 72 49[ (4 2 ][ ( 6 )3 ]5 33.12(9 - 3)( 6 )1263 · 5 612615 612 615-12)3 542. 63 216(4 · 643 · 63 34.3(5 1)63m69x ·x xm 6 9m 6-6 9-6m 3x3 · x6 x925)3y y643.yn25 - n 625 - n - 25 6 - 25-n -19-n · (-1) -19 · (-1)n 1925y y6y19 43 · 63-3 43 · 60 64 · 1 64Copyright by Houghton Mifflin Harcourt.All rights reserved.Product of PowersProperty36. Sample answer: The product of two fractions is theproduct of the numerators over the product of thedenominators. Writing this as a product of fractionslets you simplify them separately, using the Quotientof Powers Property to simplify the second fraction. 64 1 430. 3 40 · 9210

52. -32 -9-33 -27-34 -81-35 -243;( -3 )2 9( -3 )3 -27( -3 )4 81( -3 )5 -243For -an, you get -9, -27, -81, and -243.For (-a)n, you get 9, -27, 81, and -243. No, it doesnot appear that -an (-a)n. When n is even, thetwo expressions are opposites. When n is odd, thetwo expressions are equal.44. Sample answer: Dividing is the same as multiplyingby the reciprocal. So when dividing powers with thesame base, you add the opposite of the exponent inthe denominator. This is the same as subtracting theexponents.2 103045.2 10273010 1027 1030-27 103 1,000103 kg, or 1,000 kg53. Let the number equal x.x12 125x912-9x 125x3 125The cube root of 125 is the number 5.46. 2 · 2 210 30 240240 bytes10307-247. x · x7 ( -2) x x5;x7 x2 x7-2 x5LESSON 2.2Your Turn3. Move the decimal in 6,400 to the left to get 6.4.6,400 6.4 1,000 1036,400 6.4 103757-2x ; SampleBoth expressions equal x , so x · x x2answer: When multiplying powers with the samebase, you add exponents: 7 ( -2 ) 5. Whendividing powers with the same base, you subtractexponents: 7 - 2 5. In cases like this,n-mxn .x · x xm48. The number of cubes in each row is 3 raised to therow number.4. Move the decimal in 570,000,000,000 to the left toget 5.7.570,000,000,000 5.7 100,000,000,000 1011570,000,000,000 5.7 10115. Move the decimal in 9,461,000,000,000 to the left toget 9.461.9,461,000,000,000 9.461 1,000,000,000,000 10129,461,000,000,000 9.461 1012 km98. To write 7.034 10 in standard notation, move thedecimal 9 places to the right.7.034 109 7,034,000,00049. Since the number of cubes in each row is 3 raised tothe row number, the number of cubes in Row 6 willbe 3 raised to the power 6, and the number of cubesin Row 3 will be 3 raised to the power 3.36 729;3633 36-3 33 27The number of cubes in Row 6 will be 36, or 729.There will be 33, or 27, times the number of cubes inRow 6 as there are in Row 3.59. To write 2.36 10 in standard notation, move thedecimal 5 places to the right.2.36 105 236,000610. To write 5 10 in standard notation, move thedecimal 6 places to the right.5 106 5,000,000 gGuided Practice1. Move the decimal in 58,927 to the left to get 5.8927.58,927 5.8927 10,000 10458,927 5.8927 10450. 3 3 3 3 3 3 3 9 27 81 243 729 1,092The total number of cubes in the triangle is 1,092;Sample answer: I evaluated 31, 32, 33, 34, 35, and 36and added these numbers together.1234562. Move the decimal in 1,304,000,000 to the left toget 1.304.1,304,000,000 1.304 1,000,000,000 1091,304,000,000 1.304 1093. Move the decimal in 6,730,000 to the left to get 6.73.66,730,000 6.73 1,000,000 1066,730,000 6.73 10Focus on Higher Order Thinking51. Sample answer: No, I do not agree, because26 · 6 6·66 1 1. 362 36 · 36 6 · 6 · 6 · 6 6 · 6 36Copyright by Houghton Mifflin Harcourt.All rights reserved.4. Move the decimal in 13,300 to the left to get 1.33.413,300 1.33 10,000 10413,300 1.33 1011

22. 1,000 10.5 10,50010,500 1.05 10,000 10410,500 1.05 104 mosquitoes5. Move the decimal in97,700,000,000,000,000,000,000 to the left toget 9.77.97,700,000,000,000,000,000,000 9.77 102297,700,000,000,000,000,000,000 9.77 10222,400 words40 words 60 23.1 minute 601 hour2.6 105 260,000260,000 2,400 108.31 hours, or 108 hours and 20 minutes10836. Move the decimal in 384,000 to the left to get 3.84.5384,000 3.84 100,000 105384,000 3.84 1057. To write 4 10 in standard notation, move thedecimal 5 places to the right.4 105 400,00024. a. Write 1.182 in standard notation, 1,182, and thenmultiply by your weight.98. To write 1.8499 10 in standard notation, move thedecimal 9 places to the right.1.8499 109 1,849,900,000b. Sample answer: 94,560 lb; 9.456 10425. 230 20 4,6004,600 4.6 1,000 1034,600 4.6 103 lb9. To write 6.41 10 in standard notation, move thedecimal 3 places to the right.6.41 103 6,41034126. 9.999 10 and 2 10 ; numbers in scientificnotation are written as the product of a numbergreater than or equal to 1 and less than 10, and apower of 10, so 0.641 103 and 4.38 510 are notwritten in scientific notation.710. To write 8.456 10 in standard notation, move thedecimal 7 places to the right.8.456 107 84,560,000511. To write 8 10 in standard notation, move thedecimal 5 places to the right.8 105 800,00027. a. None of the girls have the correct answer.b. Polly and Samantha have the decimal in thewrong places, causing their exponents to beincorrect. Esther has the decimal in the correctplace but miscounted the number of places thedecimal moved.1012. To write 9 10 in standard notation, move thedecimal 10 places to the right.9 1010 90,000,000,000413. To write 5.4 10 in standard notation, move thedecimal 4 places to the right.5.4 104 54,000 s28. Sample answer: Scientific notation is a quicker wayto write large numbers. Also, it’s easier to read, it’sused b

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