Transcription
ANALYTICAL GEOMETRY INTHREE DIMENSIONSPRECALCULUSCHAPTER 111
This Slideshow was developed to accompany the textbook Precalculus By Richard Wright https://www.andrews.edu/ rwright/Precalculus-RLW/Text/TOC.html Some examples and diagrams are taken from the textbook.Slides created byRichard Wright, Andrews Academyrwright@andrews.edu2
11-01 3-D COORDINATE SYSTEMIN THIS SECTION, YOU WILL: PLOT A POINT IN 3-DIMENSIONS. CALCULATE 3-DIMENSIONAL DISTANCE AND MIDPOINT. FIND AND GRAPH THE EQUATION OF A SPHERE. FIND A TRACE OF A SPHERE.3
11-01 3-D COORDINATE SYSTEM Points in 3 dimensions (x, y, z) x comes out/into of paper y is left/right z is up/down Graph by moving out the x, over the y,then up the z. Graph A(5, 6, 3) Graph B(-2, -4, 0)4
11-01 3-D COORDINATE SYSTEM Distance Formula In 2-D: π π₯2 π₯12 π¦2 π¦12 In 3-D: (just add the z) π π₯2 π₯12 π¦2 π¦12 π§2 π§125
11-01 3-D COORDINATE SYSTEM Midpoint Formula In 2-D: π π₯1 π₯2 π¦1 π¦2,22 In 3-D: (just add the z) π π₯1 π₯2 π¦1 π¦2 π§1 π§2,,2226
11-01 3-D COORDINATE SYSTEM Equation of Circle (2-D) π₯ β2 π¦ π2 π2 Equation of Sphere (3-D) (just add z) π₯ β2 π¦ π2 π§ π2 π2 Center is (h, k, j), r radius Graph by plotting the center andmoving each direction the radius Graphπ₯ 22 π¦ 12 π§ 12 16Center (2, -1, -1)π 2 16 so π 47
11-01 3-D COORDINATE SYSTEM Trace (like intercepts for a sphere) Draw the xy trace forπ₯ 2 2 π¦ 1 2 π§ 12 16Since xy trace, let π§ 0π₯ 2 2 π¦ 1 2 1 2 16π₯ 2 2 π¦ 1 2 15Center (2, -1)π 15 3.9Looks funny because a perspective drawing8
11-02 VECTORS IN SPACEIN THIS SECTION, YOU WILL: USE VECTOR OPERATIONS IN THREE DIMENSIONS. FIND THE ANGLE BETWEEN VECTORS.9
11-02 VECTORS IN SPACE Vectors in 2-D π£ΰ΄± π£1 , π£2 Vectors in 3-D (just add z) π£ΰ΄± π£1 , π£2 , π£3 To find a vector from the initial pointπ1 , π2 , π3 to the terminal pointπ1 , π2 , π3 π£ΰ΄± π1 π1 , π2 π2 , π3 π3 If π£ΰ΄± π£1 , π£2 , π£3 and π’ π’1 , π’2 , π’3 , Addition Add corresponding elements π£ΰ΄± π’ π£1 π’1 , π£2 π’2 , π£3 π’3 Scalar multiplication Distribute ππ£ΰ΄± ππ£1 , ππ£2 , ππ£310
11-02 VECTORS IN SPACE If π£ΰ΄± π£1 , π£2 , π£3 and π’ π’1 , π’2 , π’3 , Dot Product π£ΰ΄± π’ π£1 π’1 π£2 π’2 π£3 π’3 Magnitude π£ΰ΄± π£12 π£22 π£32 Unit vector in the direction of π£ΰ΄± π£π£11
11-02 VECTORS IN SPACE Angle between vectors π’ π£ΰ΄± π’π£ΰ΄± cos π If π 90 (and π’ π£ΰ΄± 0) Then vectors are orthogonal If π’ ππ£ΰ΄± Then vectors are parallel12
11-02 VECTORS IN SPACE Let π 1, 0, 3 and π 2, 1, 4 Find unit vector in direction of π Find π Find π 2ππ π12 π22 π3212 02 32 10π1, 0, 3 π10103 ,,10 10 10 10 3 10, 0,10101, 0, 3 2 2, 1, 41, 0, 3 4, 2, 8 3, 2, 513
11-02 VECTORS IN SPACE Let π 1, 0, 3 and π 2, 1, 4 Find the angle between π and π Find π π1, 0, 3 2, 1, 41 2 0 1 3 4 14π π π 14 12 0232π cos π 2 2 12 4 14 10 21 cos π 14 cos π10 21π 165.0 2 cos π14
11-02 VECTORS IN SPACE12 Are πΰ΄± 1, 5, 2 and πΰ΄± 5 , 1, 5 Parallel if πΰ΄± π πΰ΄±parallel, orthogonal, or neither?Orthogonal if πΰ΄± πΰ΄± 0Not 0, so not orthogonal121, 5, 2 , 1,55121 5 1 25514 5 655121, 5, 2 π , 1,55Check x1 π 1 π 55Check y5 π 1 π 515
Check z2 π 55c is always the same, so they are parallel 2 π15
11-02 VECTORS IN SPACE Are π 1, 1, 3 , π 0, 4, 2 , and π 6, 13, 5 collinear?Find ππ and ππ . If they are parallel, then they go in same direction.Since they would share a point, then they would be the same line.ππ 0 1, 4 1 , 2 3 1, 5, 5ππ 6 0, 13 4, 5 2 6, 9, 3These are not parallel because ππ πππ They are not going same direction, so not collinear16
11-03 CROSS PRODUCTSIN THIS SECTION, YOU WILL: EVALUATE A CROSS PRODUCT. USE A CROSS PRODUCT TO SOLVE AREA AND VOLUME PROBLEMS.17
11-03 CROSS PRODUCTS πΰ΄± is unit vector in x, πΰ΄± is unit vector in y, and π is unit vector in z π’ π’1 πΰ΄± π’2 πΰ΄± π’3 π and π£ΰ΄± π£1 πΰ΄± π£2 πΰ΄± π£3 ππΰ΄± π’ π£ΰ΄± π’1π£1πΰ΄±π’2π£2ππ’3π£3 If π’ 2, 3, 3 and π£ΰ΄± 1, 2, 1 , find π’ π£ΰ΄±πΰ΄±πΰ΄±πΰ΄±π πΰ΄±π’ π£ΰ΄± 2 3 3 2 31 2 1 1 2 3ΰ΄±π 3 πΰ΄± 4π 3π 6ΰ΄±π 2 πΰ΄± 3ΰ΄±π πΰ΄± π 3, 1, 118
11-03 CROSS PRODUCTS Properties of Cross Products π’ π£ΰ΄± π€ π’ π£ΰ΄± π€ π’ π£ΰ΄± π£ΰ΄± π’ π’ π£ΰ΄± is orthogonal to π’ and π£ΰ΄± π’ π£ΰ΄± π€ π’ π£ΰ΄± π’ π€ π’ π£ΰ΄± π’π£ΰ΄± sin π π π’ π£ΰ΄± ππ’ π£ΰ΄± π’ π π£ΰ΄± π’ π’ 0 If π’ π£ΰ΄± 0, then π’ and π£ΰ΄± areparallel19
11-03 CROSS PRODUCTS π΄ πβ β π’ sin π π΄ π£ΰ΄±π’ sin π Area of a Parallelogram π’ π£ΰ΄± where π’ and π£ΰ΄± representadjacent sides20
11-03 CROSS PRODUCTS Triple Scalar Product (shortcut)π’1 π’2 π’3 π’ π£ΰ΄± π€ π£1 π£2 π£3π€1 π€2 π€3 Volume of Parallelepiped (3-D parallelogram) π π’ π£ΰ΄± π€ where π’, π£,ΰ΄± and π€represent adjacent edges21
11-04 LINES AND PLANES IN SPACEIN THIS SECTION, YOU WILL: WRITE AN EQUATION FOR A LINE IN THREE DIMENSIONS. WRITE AN EQUATION FOR A PLANE. FIND THE ANGLE BETWEEN TWO PLANES. GRAPH A PLANE.22
11-04 LINES AND PLANES IN SPACE Lines Line L goes through points P and Q π£ΰ΄± is a direction vector for L Start at P and move any distance indirection π£ΰ΄± to get some point Q ππ π‘π£ΰ΄± because they are parallel π₯ π₯1 , π¦ π¦1 , π§ π§1 ππ‘, ππ‘, ππ‘ General form23
11-04 LINES AND PLANES IN SPACE Parametric Equations of Line Take each component of the generalform and solve for x, y, or z.π₯ ππ‘ π₯1 π¦ ππ‘ π¦1π§ ππ‘ π§1 Symmetric Equation of Line Solve each equation in parametricequations for t π₯ π₯1π π¦ π¦1π π§ π§1π We used these when we solved 3-Dsystems of equations and got manysolutions24
11-04 LINES AND PLANES IN SPACE Find a set of parametric equations of the line that passes through (1, 3, -2) and (4, 0, 1).Find the direction vector between those two points.π£ΰ΄± 4 1, 0 3,1 2 3, 3, 3 π, π, πLetβs call the first point 1, 3, 2 π₯1 , π¦1 , π§1Plug it inπ₯ ππ‘ π₯1π¦ ππ‘ π¦1π§ ππ‘ π§1π₯ 3π‘ 1π¦ 3π‘ 3π§ 3π‘ 225
11-04 LINES AND PLANES IN SPACE Planes ππ π 0 because they areperpendicular Standard form π π₯ π₯1 π π¦ π¦1 π π§ π§1 0 General form ππ₯ ππ¦ ππ§ π 026
11-04 LINES AND PLANES IN SPACE Find the general equation of plane passing through π΄ 3, 2, 2 , π΅ 1, 5, 0 , and πΆ 1, 3, 1We need to find the normal vector to the plane.Find two vectors in the planeπ΄π΅ 1 3,5 2,0 2 2,3, 2π΅πΆ 1 1, 3 5,1 0 0, 8, 1Find the cross product to get a perpendicular (normal) vectorπ π΄π΅ π΅πΆπΰ΄±πΰ΄±πΰ΄±π πΰ΄±π 2 3 2 2 30 8 1 0 8 3ΰ΄±π 0ΰ΄±π 16π 0π 16ΰ΄±π 2ΰ΄±π 13ΰ΄±π 2ΰ΄±π 16π π, π, πFill in the general formI chose π΅ 1, 5, 0 π₯1 , π¦1 , π§1π π₯ π₯1 π π¦ π¦1 π π§ π§1 0 13 π₯ 1 2 π¦ 5 16 π§ 0 0Simplify to get general form 13π₯ 2π¦ 16π§ 3 027
11-04 LINES AND PLANES IN SPACE Angle between two planes Find the angle between normalvectors Normal vectors are coefficients inthe equations of the plane π1 π2 π1π2 cos π28
11-04 LINES AND PLANES IN SPACE Distance between a Point and a Plane π· πππππ ππ π· ππ ππ29
11-04 LINES AND PLANES IN SPACE Graphing planes in space Find the intercepts Plot the intercepts Draw a triangle to represent theplane Sketch 3π₯ 4π¦ 6π§ 24x-int 3π₯ 24 π₯ 8y-int 4π¦ 24 π¦ 6z-int 6π§ 24 π§ 430
ANALYTICAL GEOMETRY IN . Some examples and diagrams are taken from the textbook. Slides created by Richard Wright, Andrews Academy rwright@andrews.edu 2. 11-01 3-D COORDINATE SYSTEM IN THIS SECTION, YOU WILL: PLOT A POINT IN 3-DIM