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Bernoulli Equation (BE)ME 305 Fluid Mechanics I BE is a simple and easy to use relation between the following three variables in amoving fluid pressurePart 5 velocity elevationBernoulli Equation It can be thought of a limited version of the 1st law of thermodynamics. It can also be derived by simplifying Newtonβs 2nd law of motion written for a fluidparticle moving along a streamline in an inviscid fluid.These presentations are prepared byDr. CΓΌneyt Sert Warning: BE is the most used and the most abused equation in fluid mechanics.So be careful !!!Department of Mechanical EngineeringMiddle East Technical UniversityMovie: StreamlinesAnkara, Turkeycsert@metu.edu.trYou can get the most recent version of this document from Dr. Sertβs web site.Please ask for permission before using them to teach. You are NOT allowed to modify them.5-15-2Streamline coordinatesDerivation of the BE Consider a fluid particle moving along a streamline in a planar flow. Main assumption behind the BE is the omission of viscous forces (inviscid flow). Its current position is given by π (π‘). Its speed is π ππ /ππ‘.ππ ππ is the direction along the streamline.Exercise : A fluid particle moves along a streamline for the following 2D, steady flowin the π₯π§ plane. Derive the steady version of the BE by considering the pressure andbody forces in the streamline direction.Streamline If the streamline is curved, ππ points towardsπ (π‘)the center of curvature.ππ π π πππ‘ π‘ π ππ π2βππ πβ : Radius ofcurvature Acceleration components areππ ππ(Note that π π(π , π‘))Newtonβs 2nd law for inviscid flowCenter ofcurvatureπ§π₯( zero for a straight streamline) Pressure, viscous and body forces acting on the particle create these accelerations. BE is derived by considering the π component of this force balance in the absence ofviscous forces.π πΏπ ππΏπ πΏπ π Net pressure force on the particle Net body force on the particle (Particleβs mass) x (Particleβs οΏ½οΏ½οΏ½π5-35-41
The Most Commonly Used Form of the BEThe Most Commonly Used Form of the BE (contβd) The following most common form of the BE is valid for steady, incompressible,inviscid flows.π 2 BE can be seen as a balance of kinetic, potential and pressure energies. Consider the flow of water from the syringe. The force applied to the plunger willproduce a pressure greater than atmospheric pressure at point 1. The water flowsfrom the needle (point 2) with relatively high velocity and rises up to point 3 at thetop of its trajectory (Reference: Munsonβs book). πππ§ constant along a streamlineUsing two points on a streamlineπ1 ππ 2ππ12ππ22 πππ§1 π2 πππ§22221BE can also be understood as βWork done on a fluid particle by pressure and gravityforces is equal to the change in its kinetic energyβ. Due to the friction effects (viscous forces) the waterwill not go up as much as predicted by the BE.Exercise : Compare the above BE with the energy conservation equation written fora uniform, steady flow in a single inlet single exit CV. Note that more general forms of the BE also exist for compressible, unsteady flows.5-5BE in ββHeadββ FormExercise : A tube can be used to discharge waterfrom a reservoir as shown. Determine the speed ofthe free jet and the minimum absolute pressure ofwater that occurs at the top of the bend.π2π π§ constant along a streamlineππ2πVelocity headTotal head (βπ )Elevationhead5-6Bernoulli Equation Exercises (contβd) Divide all the terms of the BE by ππPressureheadSuch effects arise especially at the narrow needle exitand between the water jet and surrounding airstream.BE says that totalhead is constantalong a streamline. In this form all the terms have the units of length and they are called heads. Elevation head : related to the potential energy of the fluid. Pressure head : represents the height of column of the fluid that is needed toproduce the pressure π. Velocity head : represents the vertical distance needed for the fluid to fall freely(neglecting friction) if it is to reach velocity π from rest.1m3mThis is known as siphoning. It can be used to draingas from the tank of an automobile. Once youestablish the initial flow by sucking gas from thetube, the gas will flow by itself.Exercise : Consider the flow of air around a cyclistmoving through still air with velocity π. Determinethe pressure difference between points 1 and 2.Hint : Be careful about the unsteadiness of the flowfield.5-721π5-82
Pressure Variation Normal to the Streamlines Pressure Variation Normal to the Streamlines (contβd)We can also study the force balance normal to the streamline (in the π direction). β corresponds to a straight streamline. β corresponds to a change in the flow direction, i.e. a curved streamline. Thisis accomplished by the appropriate combination of pressure gradient and fluidweight normal to the streamline. If gravitational effects are negligible (gas flows), or if the flow is in a horizontal planeπ ππ (pointing towards the center of curvature)π§β : Radius of curvature Center of curvature For steady flows we obtain the following equation (see Munsonβs book for details) ππ Therefore when streamlines are curved, pressure increases with distance away fromthe center of curvature. The pressure difference is used to balance the centrifugal acceleration associatedwith the curved streamlines.π2ππ§ π πππ πβ π ππ 2 πβ(π 2 β) is the centrifugalPressure increasesin β π directionMovieFree vortexacceleration due to directionchangeCurved streamlinesof a flow fieldπ5-95-10Pressure Variation Normal to the Streamlines (contβd) Static, Dynamic, Stagnation & Total PressuresFor straight and parallel streamlines (β ) pressure variation across thestreamlines is hydrostatic (as if the fluid is not moving)ππ ππ 2 πππ§ constant along a streamline2Static pressurePressure variation normal to thestreamlines is as if the fluid isstatic (not moving)Dynamic pressureStagnation pressureStraight and parallelstreamlines of a flowfield (β )π π§From Slide 5-9: ππ ππ 0ππ§HydrostaticpressureBE says that totalpressure is constantalong a streamline.Total pressure(Fluid statics equation)This fact will be used in studying speed measurement with a Pitot tube.5-11 Static pressure is also known as the thermodynamic pressure. To measure it onecould move with the fluid, thus being static relative to the moving fluid. It can alsobe measured using a piezometer tube (as will be seen later). Dynamic pressure represents the rise in pressure as a fluid slows down along astreamline (see the next page). At a stagnation point π 0, and stagnation and static pressures are equal.5-123
Static, Dynamic, Stagnation & Total Pressures (contβd)Simple Pitot Tube Pitot tube is a device used for speed measurement.Exercise : Consider the inviscid, incompressible, steady flow along the horizontalstreamline A-B in front of the sphere. Analytical work yields the following fluidvelocity equation along this streamline.π π0 1 It is a simple tube with a 90 degree bend. It measures flow speed using the Bernoulli principle.π 3π₯3Determine the pressure variation along the streamline from point A far away fromthe sphere (π₯π΄ , ππ΄ π0 ) to point B on the sphere (π₯π΅ π , ππ΅ π0Bπ Pitot tube on a Formula 1 carπ₯Pitot tubes on a passanger aircraft Read about the role of Pitot tube malfunctions on plane 362487/plane crashes and pitot tubes.html?cat 155-135-14Simple Pitot Tube (contβd)πππ‘πβ1β0π₯πUse of Pitot Tube with a Piezometer Fluid flows in an open channel from left to right. We want to measure the speed at point π₯. Fluid fills the Pitot tube and rises inside it to alevel of β1 above the free surface. For the flow in a closed channel or pipe weneed to use an additional tube called thepiezometer tube (static tube).β1ββ00π₯ The aim of using a Pitot tube is to create astagnation point at point ββπββ with zero velocity.Exercise: Show that the fluid speed at point π₯ is given byππ₯ πππ‘πβ22πβ1 With a Pitot tube we actually measure the pressure difference between points ββπ₯ββand ββπββ and convert this difference to a speed difference using the BE. Piezometer is used to measure the staticpressure at point π₯ asπππ₯ πππ‘π ππ(β0 β2 ) Using the Pitot tube : ππ πππ‘π ππ(β0 β1 ) BE between points π₯ and π gives the unknown speed as : ππ₯ ππ₯ 5-152(ππ ππ₯ )/π2π(β1 β2 )5-164
Combined Pitot-Static Tube (Prandtlβs Tube)ππ₯ππβπππCombined Pitot-Static Tube (contβd) Instead of measuring static pressure at point π₯using a piezometer tube, a second tube is usedaround the Pitot tube. Typical pressure variationalong a combined Pitotstatic tube is as shown. Static pressure holes (point π) of the outer tubeare located such that they measure correctupstream static pressure, i.e. ππ ππ₯ . As seen, the holes arelocated such that theymeasure the static pressureahead of the device. Two tubes provide the necessary pressuredifference measurement using the mercury in it. It is possible to use pressure transducers insteadof mercury columns to obtain accurate digitalreadings. The required pressure difference is ππ ππ₯ ππ π πβπ Using this in the BE we getππ₯ 2(ππ ππ₯ )/π ππ₯ 2πβπMunsonβs textbookExercise: Water flows through the pipecontraction shown. For the given 0.2 mdifference in the manometer level, determinethe flow rate if the small pipe diameter isa) π· 0.05 m,ππ 1πb) π· 0.03 m5-17Be Careful in Using the Bernoulli Equation5-18Extended Bernoulli Equation (EBE) The simplest and the most commonly used BE that we studied in the previous slidesmay lead to unphysical results for problems similar to the following ones. It is a modified version of the BE to include effects such as viscous forces, heattransfer and shaft work. BE will be extended in the next slide to solve some of these problems. Remember the energy conservation equation for a single inlet, single exit CV withuniform properties.π π€π π’ π π2 ππ§π 2 π’ exitπ π2 ππ§π 2inlet Arranging this equation we getπ π2 ππ§π 2 inletOriginal BEΓengel and Cimbalaβs book5-19π π2 ππ§π2 π’exit π’inlet π π€π exitFrictional work perunit mass (π€π )Shaft work doneper unit mass5-205
Extended Bernoulli Equation (contβd)π2π ππ§π 2 1π2π ππ§π212 Flow is from location 1 (upstream) to location 2 (downstream). Shaft work (π€π ) 2 π€π π€π ββHeadββ Form of the EBEStreamlineπ€πDividing both sides of the EBE by π we getππππ€π For a turbine, which converts hydraulic energy into mechanical energy, the work isdone by the fluid and π€π is negative. For a pump, which converts mechanical energy into hydraulic energy, the work isdone on the fluid and π€π is positive.Pressurehead π22πVelocityhead π§ 1Elevationheadππ2 π§ππ 2π βπ βπ 2Total head at 2(βπ 2 )FrictionheadPump orturbine headTotal head at 1(βπ 1)Frictional work (π€π ) is the amount of mechanical energy converted into thermalenergy due to viscous action. EBE can simply be written hasβπ 1 βπ 2 βπ βπ It corresponds to a rise in the internal energy of the fluid (heat up the fluid) or tothe heat that is lost to the surroundings. Although possible heat addition to the fluid is also included in this term, it isalmost always used to represent a loss (a positive quantity in the above equation).orβπ 2 βπ 1 βπ βπ Total head at a downstream location is equal to the total head at an upstreamlocation minus the head loss due to frictional losses plus the head due to shaft work.5-215-22Pump and Turbine Head (βπ ) Extended BE ExercisesPump head βπ is related to the power delivered to thefluid by the pump (π«π ) as followsπ«π ππ€π πππ€π π«π πππβπ where π is the volumetric flow rate that passesthrough the pump. Power delivered to the fluid is related to the powerconsumed by the pump (π«pump ) through the pumpefficiencyπ«ππpump π«pumpExercise : The pump shown below pumps water steadily at a volumetric rate of0.005 m3/s through a constant diameter pipe. At the end of the pipe there is anozzle with an exit area that is equal to half of the pipe area. Neglecting frictionallosses, determine the power that must be supplied to the pump, if it is working with70 % efficiency.π2π1Centrifugalpump25 m For a turbine, power extracted from the fluid is calculated in a similar way.Pump9mπ«π πππβπ 15 m7mPower produced by the turbine (π«turbine ) is smaller than the extracted fluid powerπturbine π«turbineπ«π5-235-246
Extended BE Exercises (contβd)Toricelli Equation Exercise : A pump is used to transport water between two large reservoirs. Desiredvolumetric flow rate through the suction and discharge pipes is 0.016 m3/s. Crosssectional area of the pipes are 0.004 m2. Total frictional head losses between tworeservoirs is estimated to be 2 m. Efficiency of the pump is 75 %. DetermineConsider the discharge of a liquid from a large reservoir through an orifice (hole). 1π1 π»a) the required pump head.2b) the power delivered to the water by the pump.BE between the free surface and the orifice isπ2ππ12ππ22 πππ§1 π2 πππ§222π1 π2 πππ‘π ,π§1 π§2 π» ,π1 0c) the power required to drive the pump.π2 Dischargereservoir6m(Toricelli Equation) Discharge through the orifice with an area π΄π isMovie : ToricelliSuctionreservoir2ππ»πorifice π2 π΄πPumpDischarge pipe This value will be corrected in the following slides.Suction pipe5-255-26Vena Contracta and Contraction Coefficient Vena Contracta and Contraction Coefficient (contβd)Depending on the geometry of the orifice, flow field near the exit may be as follows. Vena contracta is the cross section of the jet where thestreamlines are straight and parallel.π΄πMunsonβs bookπ΄π This is the section at which pressure is equal to πππ‘π . Contraction coefficient :π΄ππΆπ π΄π 1π΄π π΄π π΄ππ΄π π΄ππΆπ π΄π 1π΄ππΆπ π΄π /π΄πSo the correct BE should be written between the free surface and the vena contractasection, shown as π below. 01πππ2ππ12π1 πππ§1 ππ πππ§π22π»jππππ 2ππ»Contractioncoefficient 5-27Discharge through the orifice is πorifice π΄π 2ππ» πorifice πΆπ π΄π 2ππ»5-287
Velocity Coefficient and Discharge CoefficientObstruction Flow Meters The actual discharge would be even less due to viscous effects. Velocity coefficient (πΆπ£ ) corrects this to place an obstacle inside the pipeand force the fluid to accelerate andpass from a narrow area.πorifice πΆπ πΆπ£ π΄π 2ππ»Correction due toviscous effectsCorrection due togeometry Discharge coefficient (πΆπ ) combines contraction and velocity coefficientsπΆπ πΆπ πΆπ£ They are used to measure flow ratesthrough pipes. General idea is Therefore discharge through the orifice can be given asOrificemetermeasure the pressure differencebetween the low-velocity, highpressure upstream and the highvelocity, low-pressure downstream.Nozzle flowmeteruse the BE to relate this pressuredifference to the flow rate in thepipe.VenturimeterMovie : Venturi meterπorifice πΆπ π΄π 2ππ» πΆπ is determined experimentally for a given orifice geometry and for various flowconditions.5-295-30Venturi MeterVenturi Meter (contβd) π·π1π1 π2π π΄1 ππ· 24π΄2 ππ 24 Section 1 is an upstream section with an average velocity of π1. We are interested in measuring π1. Difference between π1 and π2 is measured by using static holes. ππ· 2ππ 2π π4 14 2Combine these two equations to eliminate π1 and obtain π2 asπ2 Section 2 is the throat of the Venturi. It is also the vena contracta due to the smoothprofile of the Venturi.ππ12ππ22 π2 22Continuity equation for a CV between sections 1 and 2π΄1 π1 π΄2 π221BE between points 1 and 2 located at the centerline2(π1 π2 )π(1 π½4 )whereππ· Flow rate through the pipe is given byπ π΄2 π2 π΄25-31π½ 2(π1 π2 )π(1 π½4 )5-328
Venturi Meter (contβd) Orifice Meter This flow rate can be corrected for viscous effects using the discharge coefficientπ πΆπ π΄22 (π1 π2 )π 1 π½4,π½ ππ·π·Experimentally determined andprovided by the manufacturer(see the Slide 5-35). For the orifice meter the expansion is abrupt and πΆπ is not 1, i.e. vena contractaarea is smaller than the orifice area.π1o1ππ· 2π΄1 4π2πππ 2π΄π 42π΄2 πΆπ π΄π(vena contracta)For the nozzle flow meter the same equation can be used. Note that for the Venturi meter and the nozzle flow meter, the contraction is smoothand the contraction coefficient is 1 (πΆπ 1).5-33πΆπ Graphs for Obstruction Flow Meters0.661.000.64πΆπorificeDVd0.62π½ D0.94104105π½ 0.20.58104105106π π ise : (Munsonβs book) What diameter orifice hole is needed if under idealconditions the flowrate through the orifice meter is to be 113 L/min of water withπ1 π2 16.34 kPa ? Pipe diameter is 5 cm and the contraction coefficient is0.63.1.000.98πΆπVenturiRange of valuesdepending on specificVenturi geometry0.960.94104Following slide 5-32 a new equation can be derived for π2 . The effect of πΆπ 1 willbe seen. But in practice the equation of Slide 5-32, derived for Venturi meter, isgenerally used, with πΆπ including the effect of πΆπ too.Exercise : (Munsonβs book) a) Determine the flowrate through the Venturi metershown. b) At what flowrate the cavitation will begin if π1 376 kPa and vaporpressure of the flowing fluid is 3.6 kPa.0.960.60Section 2 is the vena contracta section. π2 is measured here. π½ 0.8πΆπnozzleπ 0.7π· Obstruction Flow Meter Exercisesπ½ 0.20.98 Section o has the orifice plate with the hole diameter π.105π π1071085-355-369
Obstruction Flow Meters (contβd) Comparison of obstruction type flow metersOrifice meterNozzle flow meterVenturi meter CostEase of InstallationCheapDifficultPressure LossHighMediumDifficultMediumHighDifficultLowOther types flow meters RotameterThermal flow measurementVortex type flow meter( youtube.com/watch?v 2dfIWNYJwZM )( youtube.com/watch?v YfQSf2NBGqc )( youtube.com/watch?v GmTmDM7jHzA ) Ultrasonic flow meterCoriolis flow measurement( youtube.com/watch?v Bx2RnrfLkQg )( youtube.com/watch?v XIIViaNITIw ) Turbine flow meterWeirs (for open channels)5-3710
Streamline 5-4 Main assumption behind the BE is the omission of viscous forces (inviscid flow). Exercise : A fluid particle moves along a streamline for the following 2D, steady flow in the plane. Derive the steady version of the BE by considering the pressure and body forces in the